Answer:
There are 1.9926 * 10 ^24 atoms.
Explanation:
M ( Mg ) = 80.45 g
We can find the molar mass of magnesium in the Periodic table:
M ( Mg ) = 24.31 g / mole
n = 80.45 g : 24.31 g/mole = 3.31 moles
N a ( Avogadro`s constant ) = 6.02 * 10 ^23
N = Na * n = 6.02 * 10 ^24 * 3.31 = 19.926 * 10 ^23
Answer:
D only
Explanation:
The products are the stuff on the right of the yield sign so the answer is D only.
Answer: 0.52 L of 15 M 
will be used to prepare this amount of 0.52 M base.
Explanation:
But on diluting the number of moles remain same and thus we can use molarity equation.
(to be prepared)
where,
=concentration of stock solution = 15 M
= volume of stock solution = ?
= concentration of solution to be prepared = 0.52 M
= volume of solution to be prepared = 15 L
Thus 0.52 L of 15 M will be used to prepare this amount of 0.52 M base
Answer:
The answer to this question is Gas.
The volume of sample = 2.25(1.5)(2.25) = 7.59375 cm3
Density = mass / volume
Density = 55.75 / 7.59375 = 7.34156 g/cm3
As the density of iron is 7.86 g/cm3 instead, it is not iron
