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3 years ago

How do I do the first question and second ?

Mathematics

2 answers:

ArbitrLikvidat [17]3 years ago

7 0

For the first one, the angles are vertical so they have the same measurement. Set them equal.

110 = 6x + 2; subtract 2 from both sides

108 = 6x; divide both sides by 6

18 = x

For the second one, there are a total of 180° in a triangle so set them equal to 180.

2x + 16 + 42 = 180

2x + 58 = 180; subtract 58 from both sides

2x = 122; divide both sides by 2

x = 61

I hope this helps!

asambeis [7]3 years ago

6 0

Answer for Problem 2:

x=61 degrees

Step-by-step explanation:

I'm not completely sure of problem 1, but I know what problem 2 is.

Tip: triangles always add up to 180 degrees.

1. 16+42= 58

2. 180-58= 122

3. 122 divided by 2= 61 degrees

ANSWER: x=61 degrees.

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A cube-shaped box has a volume of 1/8 of a cubic meter. What is the perimeter of each of its

belka [17]

Given:

The volume of a cube-shaped box is $\dfrac{1}{8}$ cubic meter.

To find:

The perimeter of each of its faces.

Solution:

Let "a" be the side length of the cube shaped box. Then the volume of the box is:

$V=(side)^3$

$V=a^3$

It is given that the volume of a cube-shaped box is $\dfrac{1}{8}$ cubic meter.

$a^3=\dfrac{1}{8}$

Taking cube root on both sides, we get

$a=\dfrac{1}{2}$

Now, the perimeter of each face of a cube is:

$P=4a$

Where, a is the side length of the cube.

Putting $a=\dfrac{1}{2}$ , we get

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2 years ago

Can you please help me solve this equation? x+9−3≤14

aleksley [76]

X+9-3≤14

Add 3 to the other side. (do the inverse of subtraction)

x+9≤17

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I hope this helps!
~kaikers

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2 years ago

I need alot of help figuring out this problemm TRIG HW

leva [86]

Answer:

x = 15

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Step-by-step explanation:

This is a special right triangle with angle measures 30° 60° 90°

The side lengths should be x 2x x√3

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2 years ago

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taurus [48]

Answer:

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Step-by-step explanation:

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Tatiana [17]

Answer:

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