2 years ago

I really need help asap!!!!!!!!!!!!!!

Mathematics

1 answer:

gogolik [260]2 years ago

4 0

The answer i B just finished this.

You might be interested in

PLEASE HELP WILL GIVE BRAINLIEST

maw [93]

Answer:

The answer would be...5(x + 2y minus 3)

3 0

2 years ago

Read 2 more answers

Divide. 83 ÷ 9 Enter your answer by filling in the boxes. __R __

forsale [732]

9R2

83/9 = 9.2222222

9*9 = 81

83-81 = 2

5 0

2 years ago

Read 2 more answers

ben is making trail mix for 25 people. each person will get 1/8 pound of trial mix. how much trail mix does ben need to make it

worty [1.4K]

ITS 100 trAilmix be because you multiply 25 Times 1/8 and multiply the answer OF 25 Times 1/8 in 25

8 0

3 years ago

ten people put there name into two different drawings. The first drawing is a trip to hawaii and the second is a new car. what i

kondor19780726 [428]

Answer:

unlikely

Step-by-step explanation:

thats alot of people

3 0

3 years ago

For a normal distribution with μ=500 and σ=100, what is the minimum score necessary to be in the top 60% of the distribution?

STatiana [176]

Answer:

475.

Step-by-step explanation:

We have been given that for a normal distribution with μ=500 and σ=100. We are asked to find the minimum score that is necessary to be in the top 60% of the distribution.

We will use z-score formula and normal distribution table to solve our given problem.

$z=\frac{x-\mu}{\sigma}$

Top 60% means greater than 40%.

Let us find z-score corresponding to normal score to 40% or 0.40.

Using normal distribution table, we got a z-score of $-0.25$ .

Upon substituting our given values in z-score formula, we will get:

$-0.25=\frac{x-500}{100}$

$-0.25*100=\frac{x-500}{100}*100$

$-25=x-500$

$-25+500=x-500+500$

$x=475$

Therefore, the minimum score necessary to be in the top 60% of the distribution is 475.

3 0

2 years ago