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USPshnik [31]
3 years ago
6

Totsakan spent $36.54 on envelopes. If they cost 4.06/box how many boxes did her buy?

Mathematics
2 answers:
never [62]3 years ago
5 0

9 boxes were bought by Totsakan for $36.54 which $4.06 costs each envelope.

Step-by-step explanation:

Total money spent on buying envelopes= $36.54

Cost of one envelope= $4.06 per box

Total no. of envelopes Totsakan bought =\frac{\text { Total money spent on buying envelopes }}{\text { Cost of One Envelope }}=\frac{36.54}{4.06}=9  Hence, Totsakan bought 9 boxes in total which it costs $36.54.

Ivahew [28]3 years ago
4 0
9 because you divide 36.54 by 4.06 i’m pretty sure
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m = Δy/Δx

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Joelle is working on a school report in a word processor. She wants to place a figure which is 13.09 \text{ cm}13.09 cm13, point
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3 years ago
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A college requires applicants to have an ACT score in the top 12% of all test scores. The ACT scores are normally distributed, w
DochEvi [55]

Answer:

a) The lowest test score that a student could get and still meet the colleges requirement is 27.0225.

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c) The lowest score that would meet the colleges requirement would be decreased to 26.388.

Step-by-step explanation:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

\mu = 21.5, \sigma = 4.7

a. Find the lowest test score that a student could get and still meet the colleges requirement.

This is the value of X when Z has a pvalue of 1 - 0.12 = 0.88. So it is X when Z = 1.175.

Z = \frac{X - \mu}{\sigma}

1.175 = \frac{X - 21.5}{4.7}

X - 21.5 = 1.175*4.7

X = 27.0225

The lowest test score that a student could get and still meet the colleges requirement is 27.0225.

b. If 1300 students are randomly selected, how many would be expected to have a test score that would meet the colleges requirement?

Top 12%, so 12% of them.

0.12*1300 = 156

156 would be expected to have a test score that would meet the colleges requirement

c. How does the answer to part (a) change if the college decided to accept the top 15% of all test scores?

It would decrease to the value of X when Z has a pvalue of 1-0.15 = 0.85. So X when Z = 1.04.

Z = \frac{X - \mu}{\sigma}

1.04 = \frac{X - 21.5}{4.7}

X - 21.5 = 1.04*4.7

X = 26.388

The lowest score that would meet the colleges requirement would be decreased to 26.388.

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Answer:

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Try this option:
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