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Snezhnost [94]
3 years ago
8

Jose Rodriguez's checking account had a starting balance of $1,234.56. He wrote a check for $115.12 End of exam for plumbing sup

plies and a check for $225.00 for a loan payment. Yesterday he deposited $96.75 in his checking account. What is Jose's current balance?
Mathematics
2 answers:
Anarel [89]3 years ago
5 0
934 894.44 994.44 991.44


answer 991.19
Darina [25.2K]3 years ago
4 0

Answer:

$894.44

Step-by-step explanation:

If Jose Rodriguez has a starting balance of $1234.56 and he writes a check of $115.12 for pumbing supplies and a check for $255 for a loan payment.

He has a remaining balance of:

=1234.56-115.12-225=894.44

If he deposited $96.75 in his account the day before these payments, then this amount is included in the starting balance of $1234.56.

Therefore Jose has a current balance of $894.44

You might be interested in
The probability that a person in the United States has type B​+ blood is 12​%. Three unrelated people in the United States are s
V125BC [204]

Answer:

The probability that all three have type B​+ blood is 0.001728

Step-by-step explanation:

For each person, there are only two possible outcomes. Either they have type B+ blood, or they do not. The probability of a person having type B+ blood is independent of any other person. So we use the binomial probability distribution to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

In which C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And p is the probability of X happening.

The probability that a person in the United States has type B​+ blood is 12​%.

This means that p = 0.12

Three unrelated people in the United States are selected at random.

This means that n = 3

Find the probability that all three have type B​+ blood.

This is P(X = 3).

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 3) = C_{3,3}.(0.12)^{3}.(0.88)^{0} = 0.001728

The probability that all three have type B​+ blood is 0.001728

4 0
3 years ago
I WILL GIVE BRAINLIEST!!!
anzhelika [568]
All I see is A
But the answer is this
Look for a graph like this

3 0
3 years ago
How is subtracting an expression similar to distributing -1
algol [13]
When you subtract you are taking away a number but also when you distribute -1 to a number it will take away 1 (because it’s negative) :-) hope this made sense!
5 0
3 years ago
4(w + 14) what the answer thank you guys :)
k0ka [10]

Answer:

4w+56

Step-by-step explanation:

4(w) = 4w

4(14)= 56

4w+56

7 0
3 years ago
Help please..........
Tom [10]
Ur graph is increasing (going up)
6 0
3 years ago
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