Answer:
HL
Step-by-step explanation:
PQ = PR {hypotenuse}
PS = PS {Reflexive property, PS is the leg of the both triangles}
∠PSQ = ∠PSR = 90
So, HL postulate
Answer:37.45hStep-by-step explanation:
you do 0.07 times 35 which gives you 2.45 then you carry the h over and add that to 35 which gives you 37.45h
The intensity of an earthquake with a magnitude of 2 is 100 times greater than the intensity of an a standard earthquake .
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What is magnitude of earthquake
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Magnitude of earthquake is the measure of the size of origin of the earthquake. The magnitude of the earthquake keeps the same value for each place.
An earthquake with a magnitude of about 2. 0 or less is called a micro-earthquake and not felt usually.The intensity of an earthquake with a magnitude of 2.
Let the intensity of this earthquake is <em>n </em>times greater than the intensity of an a standard earthquake. Thus the intensity of standard earthquake can be given as,

If the magnitude would be 3 then the intensity would be,

It would be 1000 times greater than the standard earthquake and so on.
Thus, the intensity of an earthquake with a magnitude of 2 is 100 times greater than the intensity of an a standard earthquake .
Learn more about the magnitude of earthquake here;
brainly.com/question/18109453
The answer would be C. U<span>sual, because the result is within the range of the minimum and maximum usual values.</span>
Answer:
The function in the form of fog(x) is written as 48 x² + 336 x + 590
Step-by-step explanation:
Given function as :
f(x) = 3 x² - 6 x + 5
g(x) = - 4 x - 13
So, The function in the form of fog(x) is written as
We, substitute the value of g(x) into f(x)
∴ fog(x) = 3 (g(x))² - 6 (g(x)) + 5
Or, fog(x) = 3 (- 4 x - 13 )² - 6 ( - 4 x - 13 ) + 5
or, fog(x) = 3 (16 x² + 169 + 104 x) + 24 x + 78 + 5
or , fog(x) = 48 x² + 507 + 312 x + 24 x + 78 + 5
or , fog(x) = 48 x² + 336 x + 590
So, The function in the form of fog(x) = 48 x² + 336 x + 590
Hence The function in the form of fog(x) is written as 48 x² + 336 x + 590 Answer