X = 25cm , i used pythagoras theorem to calculate this, 7^2 + 24^2 = 625, the square root of 625 = 25
Let Home runs = X
Triples would be X-3 ( 3 less triples than home runs)
Doubles would be 3x ( 3 times as many doubles as home runs)
Singles would be 45(x-3) ( 45 times as many singles as triples)
Simplify the equation for singles to be 45x-153
Now you have X + x-3 + 3x + 4x-135 = 262
Simplify:
50x - 138 = 262
Add 138 to both sides:
50x = 400
Divide both sides by 50:
x = 400/50
x = 8
Home runs = x = 8
Triples = x-3 = 8-3 = 5
Doubles = 3x = 3(8) = 24
Singles = 45(x-3) = 45(8-3) = 45(5) = 225
Answer:
The probability is 0.0052
Step-by-step explanation:
Let's call A the event that the four cards are aces, B the event that at least three are aces. So, the probability P(A/B) that all four are aces given that at least three are aces is calculated as:
P(A/B) = P(A∩B)/P(B)
The probability P(B) that at least three are aces is the sum of the following probabilities:
- The four card are aces: This is one hand from the 270,725 differents sets of four cards, so the probability is 1/270,725
- There are exactly 3 aces: we need to calculated how many hands have exactly 3 aces, so we are going to calculate de number of combinations or ways in which we can select k elements from a group of n elements. This can be calculated as:

So, the number of ways to select exactly 3 aces is:

Because we are going to select 3 aces from the 4 in the poker deck and we are going to select 1 card from the 48 that aren't aces. So the probability in this case is 192/270,725
Then, the probability P(B) that at least three are aces is:

On the other hand the probability P(A∩B) that the four cards are aces and at least three are aces is equal to the probability that the four card are aces, so:
P(A∩B) = 1/270,725
Finally, the probability P(A/B) that all four are aces given that at least three are aces is:

Answer:
129 - 280 = 51.. So the answer is 51%