A cake is created by assembling two layers as shown in the diagram below. The exposed surfaces of the cake require frosting.

Mathematics

1 answer:

Hatshy [7]2 years ago

8 0

Answer:

Step-by-step explanation:

352 is the answer

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I'm really bad at these questions

Diano4ka-milaya [45]

Answer:

30 centimeters^2

Step-by-step explanation:

The area of a triangle can be found using the following formula.

A= (b*h)/2

In this triangle, the base is 12 cm. The height is 5 cm, since it forms a right angle with the base.

b= 12 cm

h= 5 cm

A= (12 cm * 5 cm) / 2

Solve inside the parentheses first. Multiply 12 cm and 5 cm.

A= (60 cm^2) / 2

Divide 60 cm^2 by 2

A= 30 cm ^2

The area of the triangle is 30 square centimeters.

6 0

2 years ago

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Which equation is true for the value b= 10?

ArbitrLikvidat [17]

The answer to the question is D

7 0

2 years ago

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Fine the area of the shaped trapezium in the rectangle below

Ksenya-84 [330]

At first find the area of rectangle:
(x + 4)*(x + 1) = x^2 + 5x + 4
Then find the area of triangle:
$\frac{(x+1)(x-3)}{2} = \frac{x^2-2x-3}{2}$
Then you must do like this
Area of rectangle - Area of triangle = Area of the shaded
x^2+5x+4 - ( $\frac{x^2-2x-3}{2}$ )

7 0

2 years ago

Which is the simplified form of the expression ((p squared) (q Superscript 5 Baseline)) Superscript negative 4 Baseline times ((

Alexus [3.1K]

Answer:

$q^{-30}$

Step-by-step explanation:

Given the expression:

$((p^2) (q ^5)) ^{-4} X ((p ^{-4}) (q^5)) ^{-2}$

First, we open the outer brackets

$=(p^{2X-4}) (q ^{5X-4})X (p ^{-4X-2}) (q^{5X-2})\\\\=(p^{-8}) (q ^{-20})X (p ^{8}) (q^{-10})\\\\$Next, we can collect like terms\\\\=p^{-8}Xp ^{8}Xq ^{-20}Xq ^{-10}\\\\$Applying addition law of indices\\\\=p^{-8+8}Xq^{-20+(-10)}\\\\=p^0 X q^{-30}\\\\=1 X q^{-30}\\\\=q^{-30}$