Ask question

Ask question

All categories

3 years ago

8

NEED HELP WITH THIS NOW PEOPLE NOT TOMORROW OR NEXT WEEK AND DONT JUST GIVE ME ONE ANSWER DAMMIT I NEED ALLLLL!!!!! REWARD BRAIN

LIEST!!!

1 answer:

sertanlavr [38]3 years ago

5 0

Answer:

1.Down 2.(1,4) 3.x=3 4. $y\geq 3\\$ 5.-4

Step-by-step explanation:

This are your answers and they are correct i solved them and i hope this helps u too.

Hope this helps;)

Pls mark brainlist

You might be interested in

Help me ASAP<br>factorise; a=b-bx<br>10 points to whoever answers this

Serhud [2]

Answer:

a=-b(x-1)

Step-by-step explanation:

Is it factored, but that question doesn't have too much helpful in it

6 0

3 years ago

Read 2 more answers

What is the value of x?

NemiM [27]

Alternate interior angles are congruent. Therefore, set the two angles equal to each other and solve for x.

3x+4= 115
3x+4 -4 = 115 -4

3x = 111
x= 111/3---> 37. Therefore, x = 37.

4 0

3 years ago

-7/9m=11/6 solve for m

nalin [4]

m=−3314m=-3314

Decimal Form:

m=−2.35714285…m=-2.35714285…

Mixed Number Form:

m=−2514

4 0

3 years ago

In a large population, 60% of the people have been vaccinated. If 4 people are randomly selected, what is the probability that A

gulaghasi [49]

Answer:

0.9744 probability that AT LEAST ONE of them has been vaccinated

Step-by-step explanation:

For each person, there are only two possible outcomes. Either they have been vaccinated, or they have not. The probability of a person having been vaccinated is independent of any other person. So we use the binomial probability distribution to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

In which $C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

And p is the probability of X happening.

60% of the people have been vaccinated.

This means that $p = 0.6$

If 4 people are randomly selected, what is the probability that AT LEAST ONE of them has been vaccinated?

This is

$P(X \geq 1)$ when $n = 4$ .

We have that

$P(X \geq 1) = 1 - P(X = 0)$

In which

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 0) = C_{4,0}.(0.6)^{0}.(0.4)^{4} = 0.0256$

$P(X \geq 1) = 1 - P(X = 0) = 1 - 0.0256 = 0.9744$

0.9744 probability that AT LEAST ONE of them has been vaccinated

5 0

3 years ago

Whenx = -1, what is the value of y

Marta_Voda [28]

Answer: 5

the line crosses the y axis at 5

4 0

3 years ago