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3 years ago

Please i need help it’s urgent

Mathematics

1 answer:

777dan777 [17]3 years ago

8 0

Answer:

4.5

Step-by-step explanation:

6x + 42 = 18x - 12 (alternate angles)

or, 18x - 6x = 42+12

or, 12x = 54

or, x = 54/12

x= 4.5

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Solve the differential equation.<br><br> x y^2 y' = x + 1

timurjin [86]

$x y^2 y' = x + 1 \ \Rightarrow\ y^2 \frac{dy}{dx} = \frac{x+1}{x}\ \Rightarrow\ y^2 dy = \left(1 + \frac{1}{x}\right) dx\ \Rightarrow \\
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\int y^2 dy = \int \left(1 + \frac{1}{x}\right) dx\ \Rightarrow \frac{1}{3}y^3 = x + \ln|x| + C\ \Rightarrow \\
y^3 = 3x + 3\ln|x| + 3C\ \Rightarrow\ \\ \\y = \sqrt[3]{3x + 3\ln|x| + K}, \text{ where $K = 3C$}$

5 0

3 years ago

What is the explict formula for the arithmetic sequence -7.5,-9,-10.5,-12

elena-14-01-66 [18.8K]

Answer:

Step-by-step explanation:

the explicit formula for the arithmetic sequence has the form

x = a + d(n−1)

a is the first term and d is the common difference

The given arithmetic sequence is

-7.5,-9,-10.5,-12

The first term is -7.5

d = common difference = -9 - (-7.5) = -1.5

∴ x = -7.5 - 1.5(n−1)

8 0

4 years ago

George has just enough money to buy 3 chocolate and 2 ice cream cones.for the same amount of money, he could buy exactly 9 choco

charle [14.2K]

Answer:

it is impossible if u

Step-by-step explanation:

dont know the amount of money

4 0

3 years ago

Read 2 more answers

I need help with a & c please!

jeka94

The answer to a is 12 and the and the answer to c is367

3 0

3 years ago

A sample of blood pressure measurements is taken for a group of adults, and those values (mm Hg) are listed below. The values ar

Kobotan [32]

Answer:

The coefficient of variation for the systolic measurements is 12.8 %

The coefficient of variation for the diastolic measurements is 16.3 %

Therefore, we can conclude that the systolic measurements are less dispersed as compared to diastolic measurements.

Step-by-step explanation:

The coefficient of variation is the ratio of standard deviation of the data to the mean of the data. It shows the dispersion in the data set.

Coefficient of variation for the systolic measurements:

Mean = μ = (120 + 128 + 156 + 98 + 154 + 122 + 118 + 136 + 128 + 120)/10

Mean = μ = 1280/10

Mean = μ = 128

Standard deviation = σ = $\sqrt{\frac{1}{N}\sum_ (x-\mu)^{2} }$

Using excel the standard deviation is found to be

Standard deviation = σ = 16.4

Coefficient of variation = σ/μ

Coefficient of variation = 16.4/128

Coefficient of variation = 0.128

Coefficient of variation = 12.8%

Coefficient of variation for the Diastolic measurements:

Mean = μ = (79 + 76 + 75 + 51 + 92 + 87 + 59 + 64 + 72 + 81)/10

Mean = μ = 736/10

Mean = μ = 73.6

Standard deviation = σ = $\sqrt{\frac{1}{N}\sum_ (x-\mu)^{2} }$

Using excel the standard deviation is found to be

Standard deviation = σ = 12

Coefficient of variation = σ/μ

Coefficient of variation = 12/73.6

Coefficient of variation = 0.163

Coefficient of variation = 16.3%

Conclusion:

We can conclude that the systolic measurements (12.8%) are less dispersed as compared to diastolic measurements (16.3%).

7 0

3 years ago