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3 years ago

Does anyone know how to do this?

Mathematics

1 answer:

Colt1911 [192]3 years ago

8 0

Sorry i dont know how

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Please help me with the below question.

VMariaS [17]

By letting

$y = \displaystyle \sum_{n=0}^\infty c_n x^{n+r}$

we get derivatives

$y' = \displaystyle \sum_{n=0}^\infty (n+r) c_n x^{n+r-1}$

$y'' = \displaystyle \sum_{n=0}^\infty (n+r) (n+r-1) c_n x^{n+r-2}$

a) Substitute these into the differential equation. After a lot of simplification, the equation reduces to

$5r(r-1) c_0 x^{r-1} + \displaystyle \sum_{n=1}^\infty \bigg( (n+r+1) c_n + (n + r + 1) (5n + 5r + 1) c_{n+1} \bigg) x^{n+r} = 0$

Examine the lowest degree term $\left(x^{r-1}\right)$ , which gives rise to the indicial equation,

$5r (r - 1) + r = 0 \implies 5r^2 - 4r = r (5r - 4) = 0$

with roots at r = 0 and r = 4/5.

b) The recurrence for the coefficients $c_k$ is

$(k+r+1) c_k + (k + r + 1) (5k + 5r + 1) c_{k+1} = 0 \implies c_{k+1} = -\dfrac{c_k}{5k+5r+1}$

so that with r = 4/5, the coefficients are governed by

$c_{k+1} = -\dfrac{c_k}{5k+5} \implies \boxed{g(k) = -\dfrac1{5k+5}}$

c) Starting with $c_0=1$ , we find

$c_1 = -\dfrac{c_0}5 = -\dfrac15$

$c_2 = -\dfrac{c_1}{10} = \dfrac1{50}$

so that the first three terms of the solution are

$\displaystyle \sum_{n=0}^2 c_n x^{n + 4/5} = \boxed{x^{4/5} - \dfrac15 x^{9/5} + \frac1{50} x^{13/5}}$

4 0

2 years ago

HELP IM GIVING BRAINLIEST!!!

Kobotan [32]

Answer:

I think H

Step-by-step explanation:

4 0

3 years ago

Read 2 more answers

6 If the altitudes of a triangle meet at one of the triangle’s vertices, then the triangle is

lyudmila [28]

Answer:

1) a right triangle

Step-by-step explanation:

One of the caractheristics of a right triangle, the one in which the sum of the two sides squared is the hypotenuse squared(Pytagorean Theorem), is also the the altitudes of a triangle meet at one of the triangle’s vertices. So 1) is the answer to this question.

4 0

2 years ago

Solve 5x – 2y = 11 for y.

Yuki888 [10]

Answer
42

step by step
5 times 11 - 2 times 11

3 0

3 years ago

A trader made a profit of 24% by selling an article for 3,720cedis how much should he have sold it to make a profit of 48%

arsen [322]

The answer is 7440
24%=3720
48%= 3720*2
48% = 7440

6 0

2 years ago