It's negative. If it had no correlation then they would be all over the place, with this you can see a steady decline.
13 143rds would be written as 13/143.
Given
mean of 406 grams and a standard deviation of 27 grams.
Find
The heaviest 14% of fruits weigh more than how many grams?
Explanation
given
mean = 406 gms
standard deviation = 27 gms
using standard normal table ,
![\begin{gathered} P(Z>z)=14\% \\ 1-P(Zso , [tex]\begin{gathered} x=z\times\sigma+\mu \\ x=1.08\times27+406 \\ x=435.16 \end{gathered}](https://tex.z-dn.net/?f=%5Cbegin%7Bgathered%7D%20P%28Z%3Ez%29%3D14%5C%25%20%5C%5C%201-P%28Zso%20%2C%20%5Btex%5D%5Cbegin%7Bgathered%7D%20x%3Dz%5Ctimes%5Csigma%2B%5Cmu%20%5C%5C%20x%3D1.08%5Ctimes27%2B406%20%5C%5C%20x%3D435.16%20%5Cend%7Bgathered%7D)
Final Answer
Therefore , The heaviest 14% of fruits weigh more than 435.16 gms
Given:
w be the weight in pounds of a baby tigers.
To find:
The inequality if baby tigers can be no larger than 4 pounds.
Solution:
Baby tigers can be no larger than 4 pounds. It mean weight of baby tigers cannot be greater than 4. In other words, the weight of the baby tigers must be less than or equal to 4.
Let w represents weight in pounds and the weight of the baby tigers must be less than or equal to 4. So,

Therefore, the required inequality is
.
Answer:
about 10
Step-by-step explanation:
62.8 = 2 pi r/2
62.8/2 = pi r
31.4/pi = pi r/pi
about 10 = r