Answer:
The average value of 
over the interval ![[-2,5]](https://tex.z-dn.net/?f=%5B-2%2C5%5D)
is 
.
Step-by-step explanation:
Let suppose that function is continuous and integrable in the given intervals, by integral definition of average we have that:
(1)
(2)
By Fundamental Theorems of Calculus we expand both expressions:
(1b)
(2b)
We obtain the average value of over the interval ![[-2, 5]](https://tex.z-dn.net/?f=%5B-2%2C%205%5D)
by algebraic handling:
![F(5) - F(3) +[F(3)-F(-2)] = 40 + (-30)](https://tex.z-dn.net/?f=F%285%29%20-%20F%283%29%20%2B%5BF%283%29-F%28-2%29%5D%20%3D%2040%20%2B%20%28-30%29)
The average value of over the interval is .
Answer:
Step-by-step explanation:
C(F) is the degrees Celsius given the degrees Fahrenheit.<span />
Answer:
Step-by-step explanation:
1. 6w*2v + 3*6w= 12vw + 18w
2. 7(-5v) - 7(8)= -35v - 56
3. 2x*(-2x) - 3(2x) = -4x^2 - 6x
4. -4*v - 4(1)= -4v - 4
5. 2n*6n + 2n + 2*6n + 2= 12n^2 + 14n + 2
6. 4n(2n) + 4n(6) + 2n + 6= 8n^2 + 26n + 6
7. x(6x) - 2x - 18x + 6 = 6x^2 - 20x + 6
8. 8p(6p) + 8p(2) - 2(6p) - 4 = 48p^2 + 16p - 12p - 4= 48p^2 + 4p - 4
9. 6p(5p) - 6p(8) + 8(5p) - 40= 30p^2 - 48p + 40p - 40= 30p^2 - 8p - 40
10. 3m(8m) + 3m(7) - 8m - 7 = 24m^2 + 21m - 8m - 7= 24m^2 + 13m - 7
11. 2a(8a) - 2a(5) - 8a + 5 = 16a^2 - 10a - 8a + 5 = 16a^2 - 18a + 5
12. 5n(5n) - 5n(5) + 6(5n) - 6(5)= 25n^2 - 25n + 30n - 30= 25n^2 + 5n - 30
13. 4p(4p) - 4p - 4p + 1 = 16p^2 - 8p +
14. 7x(5x) + 7x(6) -6(5x) - 6(6)= 35x^2 + 42x - 30x - 36= 35x^2 + 12x - 36
Answer:
0
Step-by-step explanation:
