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Anna71 [15]
3 years ago
5

given the graphic the function f(x) below, what happens to f(x) when x is a very large positive number?

Mathematics
1 answer:
kolezko [41]3 years ago
5 0

you are a bif poop nose

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Sara bought a new modem for $85, and a sales tax of $5.95 was added to the cost of the product. What was the sales tax rate?
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Step-by-step explanation:

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3 years ago
7.
fomenos
SFF = (r/n)/{(1+r/n)^nt-1} ------- where SFF = Sinking fund factor, r = Annual interest rate, n= number of payments per year, t = number of years

Substituting,
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ABC has coordinates of A (-8,-8), B (4,-2), and C (2,2). Find the coordinates of its image after a dilation centered at the orig
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3 years ago
1) 1/2 + 11/12 + 4/6 =?
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3 years ago
According to records from 50 years, there is a 2/3 chance of June temperatures being above 80 F. Azul needs to find the probabil
Brrunno [24]

Record of june temperature of last 50 years

Probability of June temperature being above 80° F from last 50 years

                      =\frac{2}{3}

It means , out of 30 days ,there are  only 20 days , in which temperature is above 80°F.

⇒Probability that it will be above 80° F for 20 or more days this June

                =\frac{20+x}{30}  

where, x is the number of extra days after 20 days in month of june, when temperature is above 80°F.

Value of this Probability will be in between

                \frac{2}{3}\leq P \leq 1  

Now, what Azul wants

 To find the probability that it will be above 80° F for 20 or more days this June.

The Simulation given is

  ⇒There are 30 days in June. If we use a number cube with the numbers 1-6 and assign 1-4 as a temperature above 80° F and 5-6 as a temperature 80° F or below.

Total number of numbers on number cube ={1,2,3,4,5,6}

Favorable Outcome={1,2,3,4}=Temperature above 80° F

Temperature 80° F or below ={5,6}

⇒Probability of getting number {1,2,3,4} on the number cube when rolled once,that is Temperature above 80° F

        =\frac{4}{6}\\\\=\frac{2}{3}

⇒Probability of getting number {5,6} on the number cube when rolled once, that is Temperature 80° F or below

        =\frac{2}{6}\\\\=\frac{1}{3}

This is Incorrect Simulation, as there are chances that , there can be more than 20 days out of 30 days when Temperature goes above 80° F.But Here we have got Probability of temperature being above 80° F for 20 days only, not more than 20 days, which is =\frac{2}{3}

Not,a number

    \frac{2}{3}< \text{Probability} \leq 1.    

4 0
3 years ago
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