Two parallel electrodes that are typically separated by 3cm with a 5V potential difference across them.What is the magnitude of
the electric field between the two electrodes in ionization type detectors?
1 answer:
Answer:
166.67 N/C
Explanation:
Potential difference between a plate equals the product of the electric field and the distance between the plates
Δv = Ed
E = Δv / d = 5 / 0.03 since 3 cm = 0.03 m
E = 166.67 V/m = 166.67 N/C
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