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nata0808 [166]
3 years ago
9

Two parallel electrodes that are typically separated by 3cm with a 5V potential difference across them.What is the magnitude of

the electric field between the two electrodes in ionization type detectors?
Biology
1 answer:
Andre45 [30]3 years ago
3 0

Answer:

166.67 N/C

Explanation:

Potential difference between a plate equals the product of the electric field and the distance between the plates

Δv = Ed

E = Δv / d = 5 / 0.03 since 3 cm = 0.03 m

E = 166.67 V/m = 166.67 N/C

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