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4 years ago

12

17. Solve the equation. Show your work. 3x – 10 = 5x + 32

2 answers:

Ugo [173]4 years ago

5 0

Answer:

<h2>x = -21</h2>

Step-by-step explanation:

$3x-10=5x+32\qquad\text{add 10 to both sides}\\\\3x-10+10=5x+32+10\\\\3x=5x+42\qquad\text{subtract 5x from both sides}\\\\3x-5x=5x-5x+42\\\\-2x=42\qquad\text{divide both sides by (-2)}\\\\\dfrac{-2x}{-2}=\dfrac{42}{-2}\\\\\boxed{x=-21}$

ELEN [110]4 years ago

4 0

3x - 10 = 5x + 32

3x - 10 + (-5x + 10) = 5x + 32 + (-5x + 10)

-2x = 42

-0.5(-2x) = -0.5(42)

x = -21

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Answer:

Since the sample size is n=10 we can find the first quartile taking in count the first 5 observations from the data set ordered and we have this:

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We can find the third quartile taking in count the last 5 observations from the data set ordered and we have this:

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And finally the median can be calculated with the average of the two moddlie values and we got:

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And the IQr would be:

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Step-by-step explanation:

Assuming that 2 is not part of the data we have:

74, 63, 69, 62, 33, 79, 70, 60, 107, 119

We can sort the values on increasing order and we got:

33 60 62 63 69 70 74 79 107 119

Since the sample size is n=10 we can find the first quartile taking in count the first 5 observations from the data set ordered and we have this:

33 60 62 63 69

$Q_1 =62$

We can find the third quartile taking in count the last 5 observations from the data set ordered and we have this:

70 74 79 107 119

$Q_3 =79$

And finally the median can be calculated with the average of the two moddlie values and we got:

$Median= \frac{69+70}{2} =69.5$

And the IQr would be:

$IQR = 79-62= 17$

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