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kenny6666 [7]
3 years ago
8

Does this graph represent a function? What is the domain and range of the graph?

Mathematics
1 answer:
eimsori [14]3 years ago
4 0

Answer:

Yes; domain: all real numbers; range: y \geq 0

Step-by-step explanation:

1. Use the vertical line test to see if it is a function.

2. Figure out what the lowest and highest point x can be. In this case x can be any number

3. Figure out what the lowest and highest point of y can be. In this case y is not negative, the lowest it can be is 0. So y \geq 0

*Note: Domain are the x values & Range are the y values

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Brainliest and points for best answer.
jeka57 [31]

Answer:

A

Step-by-step explanation:

3 0
4 years ago
Please answer this thank you.
Nikitich [7]

11: 4,874 > 4,784 > 4,687

12: 8.09 > 8.057 > 8.023

13: 15.820 > 15.280 > 15.000

14: 43,628 > 40,628 > 34,628

15: 395.050 > 395.009 > 395.005

8 0
3 years ago
Can someone plz help me
Sati [7]

Answer:

One point greater than the last grade

Step-by-step explanation:

1. First off, N is the variable, so that means it can be any number, and when it uses the word <em>greater</em>, it means to ADD another number, which means one point greater.

6 0
3 years ago
Read 2 more answers
Carlos drew a plan for his garden on a coordinate plane. Rose bushes are located at A(–5, 4), B(3, 4), and C(3, –5)
BartSMP [9]

Given:

A(-5,4)

B(3,4)

C(3,-5)

So point D is:

so point D is (-5,-5)

For AB is

Distance between two point is:

\begin{gathered} (x_1,y_1)and(x_2,y_2) \\ D=\sqrt[]{(x_2-x_1)^2+(y_2-y_1)^2} \end{gathered}

so distance between A(-5,4) and B(3,4) is:

\begin{gathered} D=\sqrt[]{(3-(-5))^2+(4-4)^2} \\ =\sqrt[]{(8)^2+0^2} \\ =8 \end{gathered}

So AB is 8 unit apart.

For B(3,4) and C(3,-5).

\begin{gathered} D=\sqrt[]{(3-3)^2+(-5-4)^2} \\ =\sqrt[]{0^2+(-9)^2} \\ =9 \end{gathered}

So BC is 9 unit apart.

For fourth bush point is (-5,-5) it left of point C(3,-5) is:

\begin{gathered} D=\sqrt[]{(3-(-5))^2+(-5-(-5))^2} \\ =\sqrt[]{(8)^2+0^2} \\ =8 \end{gathered}

so fourth bush is 8 unit left of C.

For fourth bush(-5,-5) below to point A(-5,4)

\begin{gathered} D=\sqrt[]{(-5-(-5))^2+(4-(-5))^2} \\ =\sqrt[]{0^2+9^2} \\ =9 \end{gathered}

so fourth bush 9 units below of A.

8 0
1 year ago
I need the answer please asp
11Alexandr11 [23.1K]

Answer:

The answer is a isosceles right I think.

8 0
3 years ago
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