Your insight that the function values differ by 5 every time is very important. So your f(x) will contain 5x as a term. You have to find a constant to add or subtract to make sure f(1)=-2.
f(x) = 5x-7 does the job.
First we will calculate the distance AB.

If C is 5/9 of the distance, mathematically speaking that means:

R: The coordonate of C is 15.
Y² + 8y - 33 :
Break the expression into groups for formula ax²+ bx+c :
= (y²- 3y) + (11y - 33 )
Factor y from y² - 3y => y (y - 3)
Factor out 11 from 11 y - 33 => 11 (y - 3)
= y ( y- 3 ) + 11 ( y - 3 )
Factor out common term (y - 3 ) :
= ( y - 3 ) ( y + 11 )
hope this helps!
It's prob, It's kind of is the top left a SIx OR ZERO?!