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Tju [1.3M]
3 years ago
8

Is the formula sin2X+2sinX=0 valid?

Mathematics
1 answer:
horsena [70]3 years ago
6 0
no is not valid because according to trig identities sin2x is 2sinxcosx
so 2sinxcosx+2sinx=2sinx(cosx+1)
Hopes this loves.
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Select the correct location on the coordinate plane.
Phoenix [80]

Answer:

The length of each side is 15.

Step-by-step explanation

The length of each side is just found out by doing 60/4

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3 years ago
How many subsets are there in {1, 2, 3, 4, 5, 6}?
Contact [7]
<h3>Answer:  64</h3>

Explanation:

If there are n = 6 items in the set, then there are 2^n = 2^6 = 64 subsets

This is because there are 2 choices per slot. Either the item is in the subset or not. Since we have 6 slots, and 2 choices per slot, we have (2*2*2)*(2*2*2) = 2^6 = 64 different combos.

Side note: The empty set is included as one of the subsets. Also, the original set itself is a subset.

8 0
3 years ago
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How do I work out 1 over 4 + 3 over 8
Dmitrij [34]
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6 0
3 years ago
jose has a wedge shaped piece of wood as shown in the diagram. jose plans to paint the piece of wood and must determine how much
yulyashka [42]

Answer:

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Step-by-step explanation:

3 0
3 years ago
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A particular electronic component is produced at two plants for an electronics manufacturer. Plant A produces 70% of the compone
Vesna [10]

Answer:

If a component received by the manufacturer is defective, the probability that it was produced at plant A is 0.5385 = 53.85%.

Step-by-step explanation:

We use the Bayes Theorem to solve this question.

Bayes Theorem:

Two events, A and B.

P(B|A) = \frac{P(B)*P(A|B)}{P(A)}

In which P(B|A) is the probability of B happening when A has happened and P(A|B) is the probability of A happening when B has happened.

In this question:

Event A: Defective component

Event B: Produced at plant A.

Plant A produces 70% of the components used

This means that P(B) = 0.7

Among the components produced at plant A, the proportion of defective components is 1%.

This means that P(A|B) = 0.01

Probability of a defective component:

1% of 70%(defective at plant A)

2% of 100 - 70 = 30%(defective at plant B). So

P(A) = 0.01*0.7 + 0.02*0.3 = 0.013

If a component received by the manufacturer is defective, the probability that it was produced at plant A is

P(B|A) = \frac{0.7*0.01}{0.013} = 0.5385

If a component received by the manufacturer is defective, the probability that it was produced at plant A is 0.5385 = 53.85%.

4 0
3 years ago
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