Hello,
Very nice like question!
a)
F(2)=3 ; G(2)=2
F'(2)=0; G'(2)=1/2
P'(x)=F'(x)*G(x)+F(x)*G'(x)
P'(2)=0*2+3*1/2=3/2
b)
F(7)=5; G(7)=1
F'(7)=1/4; G'(7)=-2/3
Q'(x)=(F'(x)*G(x)-F(x)*G'(x)) / G²(x)
Q'(7)=(1/4*1-5*(-2/3))/1²=1/4+5/3=23/12
Answer:
Step-by-step explanation:
D = 3,1
E = 1,-2
F= -4,2
F=EA(e/l)
e/l=EA/F
l=Fe/EA
The coordinate of the point F which is midway from C to D as required in the task content is; +9.
<h3>What is the coordinate of the point F which is midway between C and D?</h3>
The coordinate of the point C and D as given in the task content is; -6 and +24 respectively.
Therefore, it can be inferred that the midpoint F between points C and D is;
F = (-6+24)/2
F = 18/2
F = 9.
Read more on midpoint;
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