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Elden [556K]
3 years ago
12

Solve the equation for X. 23 = 5x – 2 12 5122 25:9 esday

Mathematics
1 answer:
Snezhnost [94]3 years ago
4 0
X is 5. Hope this helps:)
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Explain hovevou could estimate 22% of 78 to check if your answer is reasonable.
fomenos

Answer:

78 rounds to 80, so find 10% of 80 and double it. 10% of 80 is 8. So, 20% of 80 is 16. Then, 22% of 78 is a little more than 16.

78 rounds to 80, and 22% is a little less than 25%. 25% (or one-fourth) of 80 is 20. So, 22% of 78 is a little less than 20.

Step-by-step explanation:

8 0
3 years ago
I will make you brainliest <br> solve this
lesya692 [45]

Step-by-step explanation:

question number 2 first part X + 2 is equal to 7 .. x is equal to 7 - 2x is equal to 5 ..second part 3 x minus 1 is equal to 3 x is equal to 23 - 1 = 3x=24 x=24÷3=x=8ans

5 0
3 years ago
All the fourth-graders in a certain elementary school took a standardized test. A total of 85% of the students were found to be
Aneli [31]

Answer:

There is a 2% probability that the student is proficient in neither reading nor mathematics.

Step-by-step explanation:

We solve this problem building the Venn's diagram of these probabilities.

I am going to say that:

A is the probability that a student is proficient in reading

B is the probability that a student is proficient in mathematics.

C is the probability that a student is proficient in neither reading nor mathematics.

We have that:

A = a + (A \cap B)

In which a is the probability that a student is proficient in reading but not mathematics and A \cap B is the probability that a student is proficient in both reading and mathematics.

By the same logic, we have that:

B = b + (A \cap B)

Either a student in proficient in at least one of reading or mathematics, or a student is proficient in neither of those. The sum of the probabilities of these events is decimal 1. So

(A \cup B) + C = 1

In which

(A \cup B) = a + b + (A \cap B)

65% were found to be proficient in both reading and mathematics.

This means that A \cap B = 0.65

78% were found to be proficient in mathematics

This means that B = 0.78

B = b + (A \cap B)

0.78 = b + 0.65

b = 0.13

85% of the students were found to be proficient in reading

This means that A = 0.85

A = a + (A \cap B)

0.85 = a + 0.65

a = 0.20

Proficient in at least one:

(A \cup B) = a + b + (A \cap B) = 0.20 + 0.13 + 0.65 = 0.98

What is the probability that the student is proficient in neither reading nor mathematics?

(A \cup B) + C = 1

C = 1 - (A \cup B) = 1 - 0.98 = 0.02

There is a 2% probability that the student is proficient in neither reading nor mathematics.

6 0
3 years ago
Find the equation of the line that contains the points P1(-4,8) and P2(-6,8)...
olga_2 [115]
The equation would just be x=8 since the x of both points is 8. 
6 0
3 years ago
HELP.. What angle pair relationship is shown?
Greeley [361]
Answer: Corresponding
7 0
3 years ago
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