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Keith_Richards [23]
3 years ago
12

SSS & SAS proofs practice I NEED HELPING ANSWERING THE LAST TWO PLEASEEE!!!! thank you!

Mathematics
1 answer:
mel-nik [20]3 years ago
3 0

Answer:

4. Corresponding angles of congruent triangles. ( Angle)

5. Common side. (Side)

6. From 1, 4, and 5. (SAS axiom)

Step-by-step explanation:

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What's the equation answer to-28= 7(n+3)
kotykmax [81]

Answer:

7n+21=-28

Step-by-step explanation:

8 0
3 years ago
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A "planet transit" is a rare celestial event in which a planet appears to cross in front of its star as seen from Earth. The pla
nikitadnepr [17]

Answer:

There is a 55.95% probability that, in the next 3,000 stars monitored by the Kepler mission, more than 4 planet transits will be seen.

Step-by-step explanation:

Assume that the number of planet transits discovered for every 3,000 stars follows a Poisson distribution with λ=5.

In a Poisson distribution, the probability that X represents the number of successes of a random variable is given by the following formula:

P(X = x) = \frac{e^{-\lambda}*\lambda^{x}}{(x)!}

In which

x is the number of sucesses

e = 2.71828 is the Euler number

\lambda is the mean in the given time interval.

For this problem, we have that \lambda = 5

What is the probability that, in the next 3,000 stars monitored by the Kepler mission, more than 4 planet transits will be seen?

That is P(X > 4). We either see 4 or less planets, or we see more than 4. The sum of the probabilities is decimal 1. So

P(X \leq 4) + P(X > 4) = 1

P(X > 4) = 1 - P(X \leq 4)

In which

P(X \leq 4) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3) + P(X = 4)

So

P(X = x) = \frac{e^{-\lambda}*\lambda^{x}}{(x)!}

P(X = 0) = \frac{e^{-5}*5^{0}}{(0)!} = 0.0067

P(X = 1) = \frac{e^{-5}*5^{1}}{(1)!} = 0.0337

P(X = 2) = \frac{e^{-5}*5^{2}}{(2)!} = 0.0842

P(X = 3) = \frac{e^{-5}*5^{3}}{(3)!} = 0.1404

P(X = 4) = \frac{e^{-5}*5^{4}}{(4)!} = 0.1755

P(X \leq 4) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3) + P(X = 4) = 0.0067 + 0.0337 + 0.0842 + 0.1404 + 0.1755 = 0.4405

Finally

P(X > 4) = 1 - P(X \leq 4) = 1 - 0.4405 = 0.5595

There is a 55.95% probability that, in the next 3,000 stars monitored by the Kepler mission, more than 4 planet transits will be seen.

6 0
3 years ago
On my 30th birthday, I plan to light 30 candles on my cake and blow 30% of them. How many candles will stay lit after I'm done?
Valentin [98]

30 candles=100%

30% of 100%= 9 candles out of 100 candles

after blowing out 30% of the candles, 9 should be left lit.


4 0
3 years ago
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A square lawn has area 200 ft squared. a sprinkler placed at the center of the lawn sprays water in a circular pattern that just
Allushta [10]

The radius will equal half of the length of a side of the square.

The length of the side for this square lawn  =  √200  so the radius will be 1/2 * √200.

Answer  7.07 feet (to nearest hundredth.

4 0
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Find the area of the surface generated by revolving x equals t plus StartRoot 2 EndRoot​, y equals StartFraction t squared Over
dezoksy [38]
Find the area of the surface generated by revolving x equals t plus StartRoot 2 EndRoot , y equals StartFraction t squared Over 2 EndFraction plus StartRoot 2 EndRoot t plus 3 , negative StartRoot 2 EndRoot less than or equals t less than or equals StartRoot 2 EndRoot about the y dash axis. The surface area obtained by revolving the given curve around the y dash axis is



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4 0
3 years ago
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