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Keith_Richards [23]
2 years ago
12

SSS & SAS proofs practice I NEED HELPING ANSWERING THE LAST TWO PLEASEEE!!!! thank you!

Mathematics
1 answer:
mel-nik [20]2 years ago
3 0

Answer:

4. Corresponding angles of congruent triangles. ( Angle)

5. Common side. (Side)

6. From 1, 4, and 5. (SAS axiom)

Step-by-step explanation:

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HELPP AND. D IS 10 it got cut out
Inga [223]

Answer: 2

Step-by-step explanation:

2

7 0
2 years ago
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Z - 1,092.8 = 1,200<br><br>A. z = 2,292.8<br><br>B. z= 2,193.8<br><br>C. z= 2,291.2
OleMash [197]

Answer:

A. z = 2292.8 is your answer

Step-by-step explanation:

Isolate the variable (z). Note the equal sign, what you do to one side, you do to the other. Add 1092.8 to both sides

z - 1092.8 (+1092.8) = 1200 (+1092.8)

z = 1200 + 1092.8

z = 2292.8

A. z = 2292.8 is your answer

~

3 0
3 years ago
Question 2 (Essay Worth 10 points)
icang [17]

Answer:

Part A: 1 solution

Part B:

3(2x-7)=3

6x-21=3

 +21  +21

6x=24

/6    /6

x=4

Step-by-step explanation:

First you <u>distribute 3(2x-7)=3</u> to 6x-21=3. Next you do inverse operations by <u>adding 21 to both sides</u> of the equation to get 6x=24. Finally you <u>divide both sides by 6</u> to get x=4

7 0
2 years ago
A piece of string is 112 inches long. The student wants to cut it into 2 pieces so that one piece is 3 times as long as the othe
gogolik [260]
37.33333333333 so about 37" I'm thinking..
3 0
3 years ago
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collect data (in decibels) of 10 different things in term of loudness. Arrange the data in ascending order &amp; find mean, medi
ss7ja [257]
Whisper-20dB
Quiet Residence-30dB
Soft stereo in Residence-40dB
Average Speech-60dB
Cafeteria-80dB
Pneumatic Jackhammer-90dB
Loud crowd noise-100dB
Accelerating Bike-100dB
Rock concert-120dB
Jet Engine (75 ft away)-140dB

(1)Mode=100dB (since 100 is occurring the maximum no. of times, i.e. it has the highest frequency of 2)
(2)Mean=sum of observations/Total number of observations
=(20+30+40+60+80+90+100+100+120+140)/10
=770/10=10dB
(3)Median= 1/2[{n/2}th observation + {(n/2)+1}th observation], where, n=total no. of observations
So, 1/2[{10/2}th observation + {(10/2)+1}th observation]
=1/2[5th observation+6th observation]
=1/2[80+90]                    [Because:5th observation=80dB and 6th=90dB]
=1/2(170)
=85
Therefore, median=85dB

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3 years ago
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