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Ne4ueva [31]
3 years ago
5

Liam is going to a carnival that has games and rides. Each game costs $5 and each ride costs $3.50. How much would Liam have to

pay if he wanted to play 3 games and go on 8 rides? How much would Liam have to pay if he wanted to play g g games and go on r r rides
Mathematics
1 answer:
lesya692 [45]3 years ago
5 0

Answer:

$43

Step-by-step explanation:

You have to find how much he is paying for his games and how much he is paying for his rides, then add them together.

5(3) = $15 (games)

8(3.5) = $28 (rides)

28+15 = 43

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Fiesta28 [93]

Answer:12063.72

Step-by-step explanation:

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3 years ago
Question 3. Find the distance between P(4,5) and the line with equation 8x + 5y = 20​
earnstyle [38]

Answer:

Step-by-step explanation:

8x+5y = 20

y = (-8/5)x + 4

slope of the line is -8/5.

slope of any perpendicular to the line is ⅝.

line of slope ⅝ that passes through P(4,5):

y-5 = ⅝(x-4)

y = ⅝x + 2.5

find intersection of lines

⅝x + 2.5 = (-8/5)x + 4

25x + 100 = -64x + 160

89x = 60

x = 60/89, y = 260/89

distance between (60/89, 260/89) and (4,5) = 3.92

8 0
3 years ago
If triangle weighs 1 gram how much does a square weigh
AleksAgata [21]

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Step-by-step explanation:

3 0
3 years ago
Read 2 more answers
The sum of two numbers is 36 twice the first number minus the second number is 6 find the numbers
Ilia_Sergeevich [38]

Answer:

14, 22

Step-by-step explanation:

x+y = 36

2×x - y = 6

=> x = 36 - y

=> 2×(36 - y) - y = 6

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3 0
3 years ago
PLEASE HELP ASAP!!! CORRECT ANSWER ONLY PLEASE!!!
Kitty [74]

Answer:   (-2, 5) and (2, -3)

<u>Step-by-step explanation:</u>

Graph the line y = -2x + 1 (which is in y = mx + b format) by plotting the y-intercept (b = 1) on the y-axis and then using the slope (m = -2) to plot the second point by going down 2 and right 1 unit from the first point:

        y - intercept = (0, 1)            2nd point = ( -1, 1).

Graph the parabola y = x² - 2x - 3 by first plotting the vertex and then plotting the y-intercept (or some other point):

y = x^2-2x-3\quad \rightarrow \quad a=1,\ b=-2,\ c=-3\\\\\text{axis of symmetry:}\ x = \dfrac{-b}{2a}\ \longrightarrow \ x=\dfrac{-(-2)}{2(1)}=\dfrac{2}{2}=1\\\\\text{y-value of vertex:}\ f(1) = (1)^2-2(1)-3\quad \longrightarrow \quad y = 1 - 2 - 3=-4\\\\\text{y-intercept:}\ f(0)= (0)^2-2(0)-3\ \longrightarrow \ y=0 - 0 - 3 = -3 \\

         vertex = (1, -4)                2nd point (y-intercept) = (0, -3)


<em>see attached</em> - the graphs intersect at two points:  (-2, 5) and (2, -3)


8 0
3 years ago
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