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3 years ago

What is the area of this parallelogram?

Mathematics

2 answers:

Mariulka [41]3 years ago

7 0

Answer:

25 cm

Step-by-step explanation:

Aleksandr-060686 [28]3 years ago

7 0

26cm thank me later.

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Which of the following is NOT equivalent to 240/300

Lyrx [107]

Two fractions are said to be equivalent if both the numerator and the numerator of one fraction can be obtained by multiplying or dividing the numerat.or and denominator of the other fraction by a single factor.

Dividing the numerator and denominator of 240/300 by 5 gives 48/60
Dividing the numerator and denominator of 240/300 by 60 gives 4/5
Dividing the numerator and denominator of 240/300 by 10 gives 24/30

Whereas dividing 300 by 2 gives 150 dividing 240 by 2 will not give 122. so 122/150 is not equivalent to 240/300.

7 0

3 years ago

-x²-8x-16=0 what is the solutions by solving by quadratic equations

Alika [10]

Answer:

x = - 4

Step-by-step explanation:

Given

- x² - 8x - 16 = 0 ( multiply through by - 1 to clear the leading negative )

x² + 8x + 16 = 0 ← this is a perfect square

(x + 4)² = 0 ( take the square root of both sides )

x + 4 = 0 ( subtract 4 from both sides )

x = - 4

6 0

3 years ago

Helppp me plsssssssss

Oliga [24]

Answer:

The class 35 - 40 has maximum frequency. So, it is the modal class.

From the given data,

$\sf \:\:\:\:\:\:\:\:\:\:x_{k}=35$
$\sf \:\:\:\:\:\:\:\:\:\:f_{k}=50$
$\sf \:\:\:\:\:\:\:\:\:\:f_{k-1}=34$
$\sf \:\:\:\:\:\:\:\:\:\:f_{k+1}=42$
$\sf \:\:\:\:\:\:\:\:\:\:h=5$

${\bf \:\: {By\:using\:the\: formula}} \\ \\$

$\:\dag\:{\small{\underline{\boxed{\sf {Mode,\:M_{o} =\sf\red{x_k + {\bigg(h \times \: \dfrac{ ( f_k - f_{k-1})}{ (2f_k - f_{k - 1} - f_{k +1})}\bigg)}}}}}}} \\ \\$

$\sf \:\:\:\:\:\:\:\:\:= 35+ {\bigg(5 \times \dfrac{(50 - 34)}{ ( 2 \times 50 - 34 - 42)}\bigg)} \\ \\$

$\sf \:\:\:\:\:\:\:\:\:\:\:\:\:\:\:= 35 +{\bigg(5 \times \dfrac{16}{24}\bigg)} \\ \\$

$\sf \:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:= {\bigg(35+\dfrac{10}{3}\bigg)} \\ \\$

$\sf \:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:(35 + 3.33) =.38.33 \\ \\$

$\:\:\sf {Hence,}\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\ \large{\underline{\mathcal{\gray{ mode\:=\:38.33}}}} \\ \\$

${\large{\frak{\pmb{\underline{Additional\: information }}}}}$

MODE

Most precisely, mode is that value of the variable at which the concentration of the data is maximum.

MODAL CLASS

In a frequency distribution the class having maximum frequency is called the modal class.

${\bf{\underline{Formula\:for\: calculating\:mode:}}} \\$

${\underline{\boxed{\sf {Mode,\:M_{o} =\sf\red{x_k + {\bigg(h \times \: \dfrac{ ( f_k - f_{k-1})}{ (2f_k - f_{k - 1} - f_{k +1})}\bigg)}}}}}} \\ \\$

Where,

$\sf \small\pink{ \bigstar} \: x_{k}= lower\:limit\:of\:the\:modal\:class\:interval.$

$\small \blue{ \bigstar}$ $\sf \: f_{k}=frequency\:of\:the\:modal\:class$

$\sf \small\orange{ \bigstar}\: f_{k-1}=frequency\:of\:the\:class\: preceding\:the\;modal\:class$

$\sf \small\green{ \bigstar}\: f_{k+1}=frequency\:of\:the\:class\: succeeding\:the\;modal\:class$

$\small \purple{ \bigstar}$ $\sf \: h= width \:of\:the\:class\:interval$

7 0

3 years ago

The product of 12 and k is 84. Solve for k.

Mrac [35]

Answer:

The product of 12 and k is 84

According to the given problem, the equation is

$\boxed{12k = 84} \\ k = \frac{84}{12} \\ \boxed{k = 7}$

k = 7 is the right answer.

5 0

2 years ago

PLEASE HELP ME I WILL GIVE U ALL MY POINTS :( please?

Alinara [238K]

Answer:

The answer is b

Step-by-step explanation:

8 0

3 years ago

Read 2 more answers