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3 years ago

Solve. i really need help z =

Mathematics

1 answer:

BlackZzzverrR [31]3 years ago

5 0

$\dfrac{7z-1}{2}=3z-2\\
7z-1=6z-4\\
7z-6z=-4+1\\
z=-3$

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4 years ago

What fractional part of 1 pound is an ounce?

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4 years ago

Write the equation for what is 15% of 24 of what number. please include the equation too

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3 years ago

Two cities have nearly the same north-south line of 117 degrees Upper W. The latitude of the first city is 29 degrees Upper N c

Mariulka [41]

Answer:

1117 km

Step-by-step explanation:

Because the two cities are approximately on the same North-South line, they are on the same longitude. The difference in their latitudes is 39° - 29° = 10°. We are subtracting because they are both in the northern hemisphere. The distance between them is

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3 years ago

Simplify . (1/c + 1/h)/(1/(c ^ 2) - 1/(r ^ 2))

Marrrta [24]

Answer:

$\frac{\left(h+c\right)cr^2}{h\left(r^2-c^2\right)}$

Step-by-step explanation:

$\frac{\frac{1}{c}+\frac{1}{h}}{\frac{1}{c^2}-\frac{1}{r^2}}$

Combine $\frac{1}{c} + \frac{1}{h}$

$\frac{\frac{h+c}{ch}}{\frac{1}{c^2}-\frac{1}{r^2}}$

Combine the bottom, too.

$=\frac{\frac{h+c}{ch}}{\frac{r^2-c^2}{c^2r^2}}$

Apply the fraction rule

$=\frac{\left(h+c\right)c^2r^2}{ch\left(r^2-c^2\right)}$

Cancel

$=\frac{\left(h+c\right)cr^2}{h\left(r^2-c^2\right)}$

Therefore, $\frac{\left(\frac{1}{c}+\frac{1}{h}\right)}{\left(\frac{1}{\left(c^2\right)}-\frac{1}{\left(r^2\right)}\right)}:\quad \frac{\left(h+c\right)cr^2}{h\left(r^2-c^2\right)}$

5 0

3 years ago