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2 years ago

Just get 10 points get some points have fun use them wizely

Mathematics

2 answers:

andrew-mc [135]2 years ago

5 0

Answer:thx

Step-by-step explanation:

masha68 [24]2 years ago

4 0

Answer:

thank you

Step-by-step explanation:

You might be interested in

Please! help and tell me the answers, or help me figure out these answers for 20 points? please! And please help me. Can anybody

max2010maxim [7]

Answer:

1. Pattern (rule) : y = x-6

2. Pattern (rule) : y=x^2+1

3. Pattern (rule) : y = -3x

4. Pattern (rule) : y = 2x-2

5. Pattern (rule) : y = x^2

Step-by-step explanation:

Note: question number correspond to your order of questions.

1. Pattern (rule) : y = x-6

for missing parts, see attached table.

2. Pattern (rule) : y=x^2+1

3. Pattern (rule) : y = -3x

4. Pattern (rule) : y = 2x-2

5. Pattern (rule) : y = x^2

5 0

3 years ago

What factors of 20 are also factors of 50

spayn [35]

The easiest way to find the factors of a pair of numbers, is simply to write out the factors until you find the ones that they have in common. So in this case, these factors would be listed as follows:
20: 1,2,4,5,10,20
50: 1,2,5,10,25,50.
From looking at these numbers, we can therefore see that the common factors are: 1,2,5,10

7 0

3 years ago

Read 2 more answers

Write an inequality to match each description. Use n for the variable.

mel-nik [20]

${\huge {\mathfrak {Answer :-}}}$

Let, the length be l and breadth be b.

So, 2(l + b) = 26

Or, l + b = 13

Or, l = 13 - b

So, we may write like this,

Area = l * b

Or, l * b > 30

Or, l (13 - l) > 30

Or, 13l - l^2 > 30

Or, l^2 - 13l + 30 > 0

Or, l^2 - 3l - 10l + 30 > 0

Or, l(l - 3) - 10(l - 3) > 0

Or, (l - 3)(l - 7) > 0

Or, l - 7 > 0

Or, l > 7.

Now, putting the value of l,

We get, l * b > 30

Or, 7 * b > 30

Or, b > 30/7

➡️ Therefore, we get,

Length > 7

Breadth > 30/7

That's it..

6 0

3 years ago

1+2-3+4+5-6+7+8-9...+97+98-99

zaharov [31]

Answer:

1584

Step-by-step explanation:

The sum of this sequence can be found a number of ways. One way is to recast it as the series whose terms are groups of three terms of the given series.

<h3>series of partial sums</h3>

The partial sums, taken 3 terms at a time, are

1+2-3 = 0

4+5-6 = 3

7+8-9 = 6

...

97+98-99 = 96

So the original series is equivalent to ...

0 +3 +6 +... +96 = 3×1 +3×2 +... +3×32 = 3×(1 +2 +... +32)

That is, the sum is 3 times the sum of the consecutive integers 1..32.

<h3>consecutive integers</h3>

The sum of integers 1..n is given by the equation ...

s(n) = n(n+1)/2

<h3>series sum</h3>

Using this to find the sum of our series, we find it to be ...

series sum = 3 × (32)(33)/2 = 1584

_____

<em>Alternate solution</em>

The given series is the sum of integers 1-99, with 6 times the sum of integers 1-33 subtracted. That is, ...

1 + 2 - 3 + 4 + 5 - 6 = 1+2+3+4+5+6 -2(3 +6) = 1+2+3+4+5+6 -6(1+2)

Continuing on to ...97 +98 -99 gives the result s(99) -6s(33).

Computed that way, we find the sum to be ...

(99)(100)/2 -6(33)(34)/2 = 4950 -3366 = 1584

3 0

2 years ago

I need help with this

Alexus [3.1K]

Answer:

i don't know

Step-by-step explanation:

6 0

3 years ago