F(x) = x²-x
g(x) =1/x
1) h(x) =f(x) -g(x) = (x²-x) - (1/x) = (x³-x²)/x (x≠0) =>
2)h(x) =f(x).g(x) = (x²-x).(1/x) =x(x²-1)
3)h(x) = f(g(x)) = (1/x)²-(1/x)
Both the areas observed participated in significant long-distance trade.
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Explanation:
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