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rusak2 [61]
3 years ago
11

A 3 by 4 rectangle is inscribed in circle. What is the circumference of the circle?

Mathematics
1 answer:
weeeeeb [17]3 years ago
7 0
look\ at\ the\ picture\\\\(2r)^2=3^2+4^2\\\\4r^2=9+16\\\\4r^2=25\ \ \ /:4\\\\r^2=\frac{25}{4}\\\\r=\sqrt\frac{25}{4}\\\\r=\frac{\sqrt{25}}{\sqrt4}\\\\r=\frac{5}{2}\\\\circumference\ of\ the\ circle:\\\\L=2\pi r;\ L=2\pi\cdot\frac{5}{2}=5\pi

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Mariana [72]

Answer:

(8x6)/2 + 9

Step-by-step explanation:

8 0
3 years ago
Whats the point of intersection between these two lines?<br><br>x+y=10<br>x+2y=14
Yakvenalex [24]
You have to make an equation that i forgot what was called but you just take
x+y=10 and multiply it by -2 so the y’s can cancel out

so you’ll end up with:

-2x-2y= -20
(+) x+2y=14

you’ll get : x = -6


then you plug in -6 for x, solve for y and your coordinates will be

(-6 , 10)
4 0
4 years ago
Read 2 more answers
The height in feet, h, of a model rocket t seconds after launch is given by the equation h(t) = 3+70t - 16t^2. The average rate
andriy [413]

Answer:

The average rate of change

\frac{dh}{d t} = 70 (1) - 16(2t)

At   t = 1

\frac{dh}{d t} = 70 (1) - 16(2t) = 38

at t=3



Step-by-step explanation:

<u><em>Step(I)</em></u>:-

The given function  h(t) = 3+70t - 16t²

                          \frac{dh}{d t} = 70 (1) - 16(2t)

The       \frac{dh}{d t} = 70 (1) - 16(2t) =0

           70 - 32 t = 0

     ⇒   70 = 32 t

   ⇒     t = \frac{70}{32} = \frac{35}{16}

<em>Step(ii</em>):-

The average rate of change in h(t) between t = 1 second and t = 3 second

\frac{dh}{d t} = 70 (1) - 16(2t)

At   t = 1

\frac{dh}{d t} = 70 (1) - 16(2t) = 38

At t = 3



8 0
3 years ago
Please help .............​
Lostsunrise [7]

In ∆ ABC and ∆ADC

AB=AD

AC=AC(common side)

BC=DC

So, ∆ABC and ∆ADC are congruent triangles,

so, m<ABC= m<ADC(corresponding angles of the congruent triangles)

x= 97°

6 0
3 years ago
Read 2 more answers
Item 16
ANTONII [103]
40 if you truly really think about it

8 0
4 years ago
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