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4 years ago

Difference between solutions of linear equations and solutions of linear in equalities

1 answer:

5 0

A linear equation is any equation involving one or two variables whose exponents are one. In the case of one variable, one solution exists for the equation. For example, with 2_x_ = 6, x can only be 3.

One obvious difference between linear equations and inequalities is the solution set. A linear equation of two variables can have more than one solution.

For instance, with x = 2_y_ + 3, (5, 1), then (3, 0) and (1, -1) are all solutions to the equation.

In each pair, x is the first value and y is the second value. However, these solutions fall on the exact line described by y = ½ x – 3/2.

If the inequality were x ? 2_y_ + 3, the same linear solutions just given would exist in addition to (3, -1), (3, -2) and (3, -3), where multiple solutions can exist for the same value of x or the same value of y only for inequalities. The "?" means that it is unknown whether x is greater than or less than 2_y_ + 3. The first number in each pair is the x value and the second is the y value.

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Is<br>Five times what number plus 10 equals 20<br>

Natalka [10]

Answer:

Step-by-step explanation:

5*2=10

10+10=20

5*x+10=20

10-10=0

20-10=10

5*x=10

5/5=0

10/5=2

x=2

3 0

4 years ago

Read 2 more answers

Identify the oblique asymptotes of f(x)=2x^2-5x+2 over x-3

kondor19780726 [428]

$\bf \cfrac{2x^2-5x+2}{x-3}\qquad 
\begin{array}{r|rrrrll}
3&2&-5&2\\
&&6&3\\
--&--&--&--\\
&2&1&5
\end{array}
\\\\\\
quotient=\underline{2x+1}\qquad remainder=5
\\\\\\
\textit{thus oblique asymptote is }y=\underline{2x+1}$

oblique/slant asymptotes occur when the degree of the numerator is exactly 1 greater than that of the denominator

and the oblique asymptote occurs at the quotient of the rational expression, notice, since the denominator is just x - 3, doing a quick synthetic division will do to get the quotient.

8 0

4 years ago

A cylinder with height 10 inches and radius 4 inches is filled with water. The water is poured into a bowl

frez [133]

Answer:

Volume of water left in the cylinder= $76\frac{2}{3}\pi \:in^3$

Step-by-step explanation:

Height of the Cylinder=10 inches

Radius of the cylinder=4 Inches

Volume of the Cylinder

$=\pi r^2h\\=4^2*10\pi\\=160\pi\:in^3$

Radius of the Hemisphere=5 Inches

$\text{Volume of a Hemisphere}=\frac{2}{3}\pi r^3\\ =\frac{2}{3}\pi *5^3\\=\frac{250\pi}{3} in^3$

Since the Volume of the cylinder is greater than the Volume of the bowl, all the water will not fit.

$\text{Therefore: volume of water left} =160\pi-\frac{250\pi}{3}\\=76\frac{2}{3}\pi \:in^3$

8 0

4 years ago

Alayna is hanging a picture frame in the center of a wall that is 8 feet wide. If the picture frame is 22 inches wide, how far w

loris [4]

Answer:The wall is 8 ft wide and the picture frame is about 2 ft wide. The sides of the picture frame will be about (8-2)/4 = 3 ft from each wall.

However, since the picture frame is actually 22 inches wide, the exact distance would be (8*12 - 22)/2 = (96 - 22)/2 = 74/2 = 37inches (3 ft 1 inch) from the wall.

Solve the problem by first subtracting the width of the picture frame from the width of the wall. That will give the length of the wall that is not covered by the frame, or the "free length". Since the picture is centered in the width of the wall, there will be an equal distance from the frame to the wall on each side of the frame. Divide the free length by 2 to get the distance from the frame to the wall. Hope its helps ;)

7 0

3 years ago

Read 2 more answers

*ANSWER TWO FOR BRAINLIEST*

REY [17]

Answer:

why u delete the answer biro it was being record ...72+ comments

4 0

3 years ago