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tia_tia [17]
3 years ago
14

A point is reflected over the y-axis to graph a new point. Are the x-coordinates of these points opposite of each other? Hewp!

Mathematics
1 answer:
musickatia [10]3 years ago
4 0
Well let's say you have a coordinate (2, -1)

Now if we reflect it upon the y-axis we'll end up at the coordinate (2,1)

We see that the x value is still the same. 
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Please help me with this, thanks guys
tangare [24]

Answer:

1) 1 | 3, 5, 8

2| 2, 4, 6, 6

3| 4, 8, 9

4| 5, 5

5| 1, 5, 6

Step-by-step explanation:

You put the tens place in the "stem" section and the ones in the "leaf" section. For 3 digit number you but both the hundreds and tens in the stem spot. Ex) 23 | 1, 5, 8, 9

6 0
2 years ago
Read 2 more answers
Solve for p:<br><br> p – 23 = -3<br> A. p = 20<br> B. p = -20<br> C. p = -26<br> D. p = 69
Alekssandra [29.7K]
P-23=-3
+23 +23

P=20

so the answer is A
6 0
2 years ago
Find the perimeter of the figure
SashulF [63]
To solve this, find the rest of the sides:

The other sides are:

1. 24 - 8 = 16
2. 23 - 9 = 14

Next, just add it up:

24 + 9 + 16 + 14 + 8 + 23 = 33 + 30 + 31 = 94
3 0
3 years ago
Mae sells newspaper subscriptions door-to-door. In addition to a fixed salary, she earns a commission for each subscription that
Lady_Fox [76]
<span>The answer is y = 10x + 125</span>
6 0
3 years ago
Read 2 more answers
Help me with this one
Artist 52 [7]

9514 1404 393

Answer:

  "complete the square" to put in vertex form

Step-by-step explanation:

It may be helpful to consider the square of a binomial:

  (x +a)² = x² +2ax +a²

The expression x² +x +1 is in the standard form of the expression on the right above. Comparing the coefficients of x, we see ...

  2a = 1

  a = 1/2

That means we can write ...

  (x +1/2)² = x² +x +1/4

But we need x² +x +1, so we need to add 3/4 to the binomial square in order to make the expressions equal:

  x^2+x+1\\\\=(x^2+x+\frac{1}{4})+\frac{3}{4}\\\\=(x+\frac{1}{2})^2+\frac{3}{4}

_____

Another way to consider this is ...

  x² +bx +c

  = x² +2(b/2)x +(b/2)² +c -(b/2)² . . . . . . rewrite bx, add and subtract (b/2)²*

  = (x +b/2)² +(c -(b/2)²)

for b=1, c=1, this becomes ...

  x² +x +1 = (x +1/2)² +(1 -(1/2)²)

  = (x +1/2)² +3/4

_____

* This process, "rewrite bx, add and subtract (b/2)²," is called "completing the square"—especially when written as (x-h)² +k, a parabola with vertex (h, k).

5 0
3 years ago
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