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3 years ago

Graphic DesignWorks employed three different salespeople last year. Person

Mathematics

2 answers:

Gnesinka [82]3 years ago

7 0

Answer:

1085.00

Step-by-step explanation:

Good luck on your test! A. P. E. X

Semenov [28]3 years ago

4 0

Answer:217.00

Step-by-step explanation:

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Refer to the accompanying data set of mean drive-through service times at dinner in seconds at two fast food restaurants. const

Anton [14]

Step-by-step explanation:

Assuming the data is as shown, restaurant X has a mean service time of 180.56, with a standard deviation of 62.6.

The standard error is SE = s/√n = 62.6/√50 = 8.85.

At 95% confidence, the critical value is z = 1.960.

Therefore, the confidence interval is:

180.56 ± 1.960 × 8.85

180.56 ± 17.35

(163, 198)

Restaurant Y has a mean service time of 152.96, with a standard deviation of 49.2.

The standard error is SE = s/√n = 49.2/√50 = 6.96.

At 95% confidence, the critical value is z = 1.960.

Therefore, the confidence interval is:

152.96 ± 1.960 × 6.96

152.96 ± 13.64

(139, 167)

4 0

3 years ago

If n is a positive integer, how many 5-tuples of integers from 1 through n can be formed in which the elements of the 5-tuple ar

sleet_krkn [62]

This question is incomplete, the complete question is;

If n is a positive integer, how many 5-tuples of integers from 1 through n can be formed in which the elements of the 5-tuple are written in increasing order but are not necessarily distinct.

In other words, how many 5-tuples of integers ( h, i , j , m ), are there with n ≥ h ≥ i ≥ j ≥ k ≥ m ≥ 1 ?

Answer:

the number of 5-tuples of integers from 1 through n that can be formed is [ n( n+1 ) ( n+2 ) ( n+3 ) ( n+4 ) ] / 120

Step-by-step explanation:

Given the data in the question;

Any quintuple ( h, i , j , m ), with n ≥ h ≥ i ≥ j ≥ k ≥ m ≥ 1

this can be represented as a string of ( n-1 ) vertical bars and 5 crosses.

So the positions of the crosses will indicate which 5 integers from 1 to n are indicated in the n-tuple'

Hence, the number of such quintuple is the same as the number of strings of ( n-1 ) vertical bars and 5 crosses such as;

$\left[\begin{array}{ccccc}5&+&n&-&1\\&&5\\\end{array}\right] = \left[\begin{array}{ccc}n&+&4\\&5&\\\end{array}\right]$

= [( n + 4 )! ] / [ 5!( n + 4 - 5 )! ]

= [( n + 4 )!] / [ 5!( n-1 )! ]

= [ n( n+1 ) ( n+2 ) ( n+3 ) ( n+4 ) ] / 120

Therefore, the number of 5-tuples of integers from 1 through n that can be formed is [ n( n+1 ) ( n+2 ) ( n+3 ) ( n+4 ) ] / 120

4 0

3 years ago

Is the following relation a function? ху 1 -2 1-3 2 1 3 - 2 Yes No

professor190 [17]

Answer:

Step-by-step explanation:

In order to be a function you should have one output for every input (or one y for every x). In this case there are multiple outputs for the number one which means the relationship isn't a function

4 0

3 years ago

Twice the sum of a number and 7 is more than 6 or at most -3. Which compound inequality can represent this relationship

yarga [219]

Answer:

Step-by-step explanation:

6 0

3 years ago

(WHO EVER HELPS ME GETS BRAINLIEST AND EXTRA POINTSSSSS :D )

Romashka [77]

Answer:d

D. 9 and 46/180

Step-by-step explanation:

6 0

2 years ago

Read 2 more answers