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andre [41]
2 years ago
13

What is the diameter of a sphere that has a diameter of 14cm?

Mathematics
1 answer:
xenn [34]2 years ago
8 0
D=2r
              <span> diameter= 14cm
so, radius= 14/2= 7cm 

</span>
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5+3w+3-w combine like terms to simplify
andreev551 [17]

Answer:

8 + 2w

Step-by-step explanation:

⇒ Change all signs to addition (subtraction is the same as adding a negative):

5 + 3w + 3 + -w

⇒ Since the expression is now all addition, you can rearrange them in any order. So group the terms together by their type:

5 + 3 + 3w + -w

⇒ Simplify:

8 + 2w

<u>Answer:</u> 8 + 2w

<em />

<em>Hope this helps!</em> :)

8 0
3 years ago
Read 2 more answers
Two last help with math please and thanks!
12345 [234]
1st problem:
Use the Pythagorean theorem:
a^2+b^2=c^2
49+361=c^2
c^2=410
c=20.24
The answer is 20m

2nd problem:
First calculate the height using the Pythagorean theorem:
a^2+b^2=c^2
20^2+b^2=625     (i got 20 {radius} by half-ing the base edge length)
400+b^2=625
b^2=225
b=15

Next, solve for the volume:
V=a^2*h/3
V=40^2*15/3
V=1600*5
V=8000

The answer is the second choice or B.

5 0
3 years ago
Read 2 more answers
A finance company offers a 36-month installment loan with an APR of 10.5%. Jerry wishes to use the loan to finance an engagement
kumpel [21]
Well i’m not sure on this but i got 18 for my answer instead of 10 so if u need any mode help im here
8 0
3 years ago
12.09 rounded to the first decimal place
bulgar [2K]
12.0 is the answer I think
4 0
3 years ago
A. The lengths of pregnancies in a small rural village are normally distributed with a mean of 266 days and a standard deviation
Darya [45]

Step-by-step explanation:

a.

mean = 266

sd = 14

cumulative probability = 0.01 so the standard score = -2.33 and 2.33 to the right and left

we find X-upper and X-lower

X-lower = 266-2.33*14 = 233.38

X-upper = 266+2.33*14 = 298.62

Between 233.38 and 298.62

we have sample size = 35

X-lower = 266-2.33*14/√35 = 260.49

X-upper = 266+2.33*14/√35 = 271.5

Between 260.49 and 271.5

b. cumulative probaility = 0.25

standard score = 1.96 to the right and left

x-lower = 6.9-1.96x0.9 = 5.14

x-upper = 6.9+1.96x0.9 = 8.66

Between 5.14 and 8.66

if sample size = 45

x-lower = 6.9-1.96*0.9/√45 = 6.64

x-upper = 6.9+1.96*0.9/√45 = 7.2

Between 6.64 and 7.2

c. standard scores would have cut off value at 0.67 and -0,67

x-lower = 265.3-0.67x15.2 = 255.12

x-upper = 265.3+0.67x15.2 = 275.48

Between 255.12 and 275.48

d. we will have critical values at 1.00 and -1.00

X-lower = 265-1x16 = 249

x-upper = 265+1x16 = 281

Between 249 and 281

with sample size = 44

x-lower = 265-1x16/√44 = 262.59

x-upper = 265+1x16/√44 = 267.41

Between 262.59 and 267.41

3 0
2 years ago
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