Answer:
15
Step-by-step explanation:
a2+b2=c2
The event "not rolling 1, 3, 4, or 5" is the same event as "rolling 2 or 6".
Since the possible outcomes of a number cube have the same probability, the probability of rolling 2 or 6 is given by
![\dfrac{\text{\# of good outcomes}}{\text{\# of possible outcomes}}=\dfrac{2}{6}=\dfrac{1}{3}](https://tex.z-dn.net/?f=%5Cdfrac%7B%5Ctext%7B%5C%23%20of%20good%20outcomes%7D%7D%7B%5Ctext%7B%5C%23%20of%20possible%20outcomes%7D%7D%3D%5Cdfrac%7B2%7D%7B6%7D%3D%5Cdfrac%7B1%7D%7B3%7D)
I think it's
![x \leqslant 5](https://tex.z-dn.net/?f=x%20%5Cleqslant%205)
I could be wrong but I think I'm right