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Angelina_Jolie [31]
2 years ago
15

Why do we use variables in math?

Mathematics
2 answers:
Phoenix [80]2 years ago
8 0

Answer:

We use it to substitute an unknown number. We have a variable for a number we don’t know and as we solve the problem we can find the answer for the variable or unknown number.

Step-by-step explanation:

I hope it helps! Have a great day!
Anygays-

Westkost [7]2 years ago
7 0

Answer:

They are used for a number we don't know what is exactly. As we solve the problem, we learn what the number could be, but when we don't know a certain number or have to solve for the unknown number, we use a variable to substitute for it.

Step-by-step explanation:

I hope it helps! Have a great day!

Pan~

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Explain why is equal to the sum of the measures of the two nonadjacent interior angles. **What is the name of the property?***
Sedbober [7]

Exterior Angle Property

Step-by-step explanation:

Interior Angle :

The angle formed with in the closed boundary of the triangle is called an interior angle.

In the given figure,  α ,  β and γ are interior angles.

Exterior Angles:

The angle formed outside the closed boundary of the triangle is called an exterior angle.

In the given figure,  γ' is an exterior angles.

Sum of the measures of the two non-adjacent interior angles  is EQUAL to  measure of an exterior angle of a triangle.

⇒   α +    β   = γ'

This property is known as " Exterior Angle Property"

Also, here angles  γ and γ' are making a linear pair.

γ +     γ'  =  180°

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3 years ago
Mr. Richard's science class is conducting a variety of experiments with projectiles and falling objects. Two groups of students
12345 [234]
<span>In general, the height of a projectile is given by

</span>h= -\frac 1 2 g t^2 + v t + h_0
<span>
where </span>h is the height at time t of a projectile shot upward at velocity v from initial height h_0<span>.

The acceleration of gravity </span>g= 9.8 \textrm {m/s}^2 \textrm{ or } g=32\textrm{ feet/s}^2.<span>  We give it a negative sign in the equation because it pulls down.

Let's apply it to each group.

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We have MKS units, positive (upward) velocity and an initial height of 0.

</span>h= -\frac 1 2(9.8) t^2 + (19) t + 0 = -4.9t^2 + 19t
<span>
Group B launches a tennis ball straight up with an initial velocity of 50 feet per second.    Not metric, velocity +50, initial height zero.

</span>h= -16t^2 + 50t
<span>
Group C drops a tennis ball from a height of 19 meters.

MKS, initial height 19, initial velocity zero.

</span>h= -\frac 1 2 g t^2 + v t + h_0 = -4.9 t^2 + 19
<span>
Group D drops a tennis ball from a height of 50 feet. 

</span>h= -16 t^2 + 50
<span>


</span>
6 0
4 years ago
Read 2 more answers
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Rufina [12.5K]

f(x)=x(x4−x2+4) hoped i helped

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3 years ago
Kyle drove 130 miles in 2.6 hours to watch a baseball game. At what rate did Kyle travel?
IRISSAK [1]

Answer:

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