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Angelina_Jolie [31]
2 years ago
15

Why do we use variables in math?

Mathematics
2 answers:
Phoenix [80]2 years ago
8 0

Answer:

We use it to substitute an unknown number. We have a variable for a number we don’t know and as we solve the problem we can find the answer for the variable or unknown number.

Step-by-step explanation:

I hope it helps! Have a great day!
Anygays-

Westkost [7]2 years ago
7 0

Answer:

They are used for a number we don't know what is exactly. As we solve the problem, we learn what the number could be, but when we don't know a certain number or have to solve for the unknown number, we use a variable to substitute for it.

Step-by-step explanation:

I hope it helps! Have a great day!

Pan~

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What’s the answer to x
grigory [225]

Answer:

x = 55

Step-by-step explanation:

a triangle's angles must equal when added up to 180.

so

76 + 49 + x = 180

combine terms

125 + x = 180

x = 55

7 0
3 years ago
Can you help me get the answer and explain to me how to do this please?
storchak [24]

Answer:

(8x+6)units

Step-by-step explanation:

its a matter of adding like terms

6 0
3 years ago
Verify sine law by taking triangle in 4 quadrant<br>Explain with figure.<br>​
Ksivusya [100]

Proof of the Law of Sines

The Law of Sines states that for any triangle ABC, with sides a,b,c (see below)

a

 sin  A

=

b

 sin  B

=

c

 sin  C

For more see Law of Sines.

Acute triangles

Draw the altitude h from the vertex A of the triangle

From the definition of the sine function

 sin  B =

h

c

    a n d        sin  C =

h

b

or

h = c  sin  B     a n d       h = b  sin  C

Since they are both equal to h

c  sin  B = b  sin  C

Dividing through by sinB and then sinC

c

 sin  C

=

b

 sin  B

Repeat the above, this time with the altitude drawn from point B

Using a similar method it can be shown that in this case

c

 sin  C

=

a

 sin  A

Combining (4) and (5) :

a

 sin  A

=

b

 sin  B

=

c

 sin  C

- Q.E.D

Obtuse Triangles

The proof above requires that we draw two altitudes of the triangle. In the case of obtuse triangles, two of the altitudes are outside the triangle, so we need a slightly different proof. It uses one interior altitude as above, but also one exterior altitude.

First the interior altitude. This is the same as the proof for acute triangles above.

Draw the altitude h from the vertex A of the triangle

 sin  B =

h

c

      a n d          sin  C =

h

b

or

h = c  sin  B       a n d         h = b  sin  C

Since they are both equal to h

c  sin  B = b  sin  C

Dividing through by sinB and then sinC

c

 sin  C

=

b

 sin  B

Draw the second altitude h from B. This requires extending the side b:

The angles BAC and BAK are supplementary, so the sine of both are the same.

(see Supplementary angles trig identities)

Angle A is BAC, so

 sin  A =

h

c

or

h = c  sin  A

In the larger triangle CBK

 sin  C =

h

a

or

h = a  sin  C

From (6) and (7) since they are both equal to h

c  sin  A = a  sin  C

Dividing through by sinA then sinC:

a

 sin  A

=

c

 sin  C

Combining (4) and (9):

a

 sin  A

=

b

 sin  B

=

c

 sin  C

7 0
3 years ago
Would the answer be 36?
umka2103 [35]

Answer:

No, it would be 72

Step-by-step explanation:

In similar triangles, the sides are different but the angles are the same. You still had a great guess though :)

Pls give brainliest

6 0
3 years ago
What is the range of the function graphed below?<br> A. 1_ B. -3 C. -2_ D. -3_
kap26 [50]
It would be B because it does to -3
3 0
3 years ago
Read 2 more answers
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