The answer is 28/55.
In order to find this, the easiest thing to do is to make both of the terms improper fractions. To do that for any term, you need to multiply the big number by the bottom of the fraction (denominator) and then add that to the top number (numerator). Then this can be expressed over the original bottom number.



Now do the same for the second fraction.



Now that we have both in that way, we can flip the second fraction and multiply. This is the same as dividing when you are using fractions.
/ 
* 

Answer:
6x³ - 8x + 9
Step-by-step explanation:
Step 1: Write out expression
2x + 7 + 6x³ - 1 + 3 - 6x - 4x
Step 2: Combine like terms (x)
6x³ - 8x + 7 - 1 + 3
Step 3: Combine like terms (constants)
6x³ - 8x + 9
Answer:
a(n)=1.15[a(n-1)]
Step-by-step explanation:
we know that

Let
a0 -----> the length of the original copy
<em>The first copy is equal to</em>
a1=1.15(a0)
<em>The second copy is </em>
a2=1.15[1.15(a0)] or a2=1.15[a1]
<em>The third copy is</em>
a3=1.15{1.15[1.15(a0)]} or a3=1.15[a2]
therefore
A recursive formula will be
a(n)=1.15[a(n-1)]
Answer:
all work is shown and pictured