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Illusion [34]
3 years ago
6

Can someone please help me to figure out the volume of this pastry bag :/

Mathematics
1 answer:
malfutka [58]3 years ago
4 0
First off,we need to understnad the formula of a cone:
\frac{1}{3} \pi \times {radius}^{2} \times height
In this case,the radius:
=5.8÷2
=2.9in

The volume of the cone:
\frac{1}{3} \pi \times {2.9}^{2} \times 16 \\ = \frac{1}{3} \pi \times 134.56 \\ = \frac{3346}{75} \pi \\ = 140.9109...

Therefore,the answer is 3365/75兀 or 140.91.

Hope it helps!
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3 years ago
Read 2 more answers
88.3 is what % of 21?
m_a_m_a [10]
88.3 is what % of 21
21 × a percent = 88.3
Divide 21 on either sides to find the percentage.
\frac{21*percentage}{21} = \frac{88.3}{21}
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2 years ago
Complex root of x^2+3x+9=0
Luden [163]

\text{Quadratic formula}

ax^2+bx+c=0\\\\\Delta=b^2-4ac\\\\x_1=\dfrac{-b-\sqrt\Delta}{2a};\ x_2=\dfrac{-b+\sqrt\Delta}{2a}

-----------------------------------------------------------------------

x^2+3x+9=0\\\\a=1;\ b=3;\ c=9\\\\\Delta=3^2-4(1)(9)=9-36=-27\\\\\sqrt\Delta=\sqrt{-27}=\sqrt{(27)(-1)}=\sqrt{27}\cdot\sqrt{-1}=\sqrt{9\cdot3}i=\sqrt9\cdot\sqrt3i=3\sqrt3i

x_1=\dfrac{-3-3\sqrt3i}{2(1)}=-\dfrac{3}{2}-\dfrac{3\sqrt3}{2}i\\\\x_2=\dfrac{-3+3\sqrt3i}{2(1)}=-\dfrac{3}{2}+\dfrac{3\sqrt3}{2}i


i=\sqrt{-1}

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