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2 years ago

What is the surface area of a rectangular prism that has i height of 2 length of 5 and width of 13

Mathematics

1 answer:

BaLLatris [955]2 years ago

7 0

Answer:

A=202

Step-by-step explanation:

A=2(wl+hl+hw)

2·(13·5+2·5+2·13)=202

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erastova [34]

Answer:

56756

Step-by-step explanation:

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3 years ago

the length of a rectangle is 2 inches longer than twice its width. If the area of the rectangle is 24 square inches, what are th

gregori [183]

Answer:

The length is 8 inches and the width is 3 inches

Step-by-step explanation:

Let w represent the width.

The length can be represented by 2w + 2

Use the area formula, A = lw, and plug in the area and the expressions for the length and width:

A = lw

24 = (2w + 2)(w)

Simplify and solve for w:

24 = 2w² + 2w

2w² + 2w - 24

Divide everything by 2:

w² + w - 12

Factor:

(w + 4)(w - 3)

Set equal to 0 and solve for each factor:

w + 4 = 0

w = -4

w - 3 = 0

w = 3

Since the width cannot be negative, the width has to be 3.

Next, find the length by plugging in 3 as w:

2w + 2

2(3) + 2

= 8

So, the length is 8 inches and the width is 3 inches

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3 years ago

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Viktor [21]

The answer is Function A. This is because Function A has a higher y-intercept than Function B. #brainliest

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2 years ago

Read 2 more answers

Select the two values of x that are roots of this equation.<br> 2x^2+ 1 = 5x

iren [92.7K]

Answer:

$\frac{5+\sqrt{17}}{4}$ , $\frac{5-\sqrt{17}}{4}$

Step-by-step explanation:

One is asked to find the root of the following equation:

$2x^2+1=5x$

Manipulate the equation such that it conforms to the standard form of a quadratic equation. The standard quadratic equation in the general format is as follows:

$ax^2+bx+c=0$

Change the given equation using inverse operations,

$2x^2+1=5x$

$2x^2-5x+1=0$

The quadratic formula is a method that can be used to find the roots of a quadratic equation. Graphically speaking, the roots of a quadratic equation are where the graph of the quadratic equation intersects the x-axis. The quadratic formula uses the coefficients of the terms in the quadratic equation to find the values at which the graph of the equation intersects the x-axis. The quadratic formula, in the general format, is as follows:

$\frac{-b(+-)\sqrt{b^2-4ac}}{2a}$

Please note that the terms used in the general equation of the quadratic formula correspond to the coefficients of the terms in the general format of the quadratic equation. Substitute the coefficients of the terms in the given problem into the quadratic formula,

$\frac{-b(+-)\sqrt{b^2-4ac}}{2a}$

$\frac{-(-5)(+-)\sqrt{(-5)^2-4(2)(1)}}{2(2)}$