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givi [52]
3 years ago
6

Assume equal likelihood for the birth of boys and girls. What is the probability that a four-child family chosen at random will

have two boys and two girls, irrespective of the order of birth
Mathematics
1 answer:
garik1379 [7]3 years ago
7 0
Each child has a 50% chance to be a girl and 50%chance to be a boy so with 4 children the probability is
\frac{1}{2}  \times  \frac{1}{2}  \times  \frac{1}{2} \times  \frac{1}{2}  =  \frac{1}{16}
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yes

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Three pounds of bananas cost $1.77.
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1.77/3=0.59

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If 3 lbs of bananas cost $1.77 we find the amount of each lbs of bananas by dividing 1.77 by 3.

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Slove this please <img src="https://tex.z-dn.net/?f=%5Csqrt%7B15n%5E2%7D%20%2A%5Csqrt%7B10n%5E3%7D" id="TexFormula1" title="\sqr
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5n^2\sqrt{6n}

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3+2 = 6

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5n^2\sqrt{6n}

4 0
1 year ago
Ryder Industries is considering a project that will produce cash inflows of $92,000 a year for five years. What is the internal
RSB [31]

Answer:

20.02%

Step-by-step explanation:

Formula : NVP = 0 =-P_0 + \frac{P_1}{(1+IRR)} + \frac{P_2}{(1+IRR)^2} + . . . +\frac{P_n}{(1+IRR)^n}

P_0 = 275000

n = 1,2,3,4,5

Substitute the values in the formula :

0 =-275000 + \frac{92000}{(1+IRR)} + \frac{92000}{(1+IRR)^2} + \frac{92000}{(1+IRR)^3}+\frac{92000}{(1+IRR)^4}+\frac{92000}{(1+IRR)^5}

275000 = \frac{92000}{(1+IRR)} + \frac{92000}{(1+IRR)^2} + \frac{92000}{(1+IRR)^3}+\frac{92000}{(1+IRR)^4}+\frac{92000}{(1+IRR)^5}

Solving for IRR using calculator

IRR = 20.02

Hence the internal rate of return if the initial cost of the project is $275,000 is 20.02%

4 0
3 years ago
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