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givi [52]
4 years ago
6

Assume equal likelihood for the birth of boys and girls. What is the probability that a four-child family chosen at random will

have two boys and two girls, irrespective of the order of birth
Mathematics
1 answer:
garik1379 [7]4 years ago
7 0
Each child has a 50% chance to be a girl and 50%chance to be a boy so with 4 children the probability is
\frac{1}{2}  \times  \frac{1}{2}  \times  \frac{1}{2} \times  \frac{1}{2}  =  \frac{1}{16}
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Item 11
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Answer:

Amount\ of\ sales=\$ 6000

Step-by-step explanation:

Let\ total\ sales=x\\\\Commission=3\%\ of\ total\ sale\\\\Commission=3\%\ of\ x\\\\It\ is\ given\ that\ salesperson\ gets\ \$ 180\ as\ commission.\\\\3\%\ of\ x=180\\\\\frac{3}{100}x=180\\\\x=\frac{180\times 100}{3}\\\\x=60\times 100\\\\x=6000\$\\\\Amount\ of\ sales=\$ 6000

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If the volume of the planter is 3,072 cubic inches, how tall is the planter?
andrezito [222]

\it \mathcal{V} =\dfrac{\mathcal{A}_b\cdot h}{3} \Rightarrow h = \dfrac{3\mathcal{V}}{\mathcal{A}_b}= \dfrac{3\cdot3072}{\mathcal{A}_b}\ \ \ \ \ (*)
\\\;\\ \\\;\\
\mathcal{A}_b = \dfrac{\ell^2\sqrt3}{4} = \dfrac{16^2\sqrt3}{4} =\dfrac{16\cdot16\sqrt3}{4} =4\cdot16\sqrt3=64\sqrt3\ \ \ \ (**)
\\\;\\ \\\;\\
(*),\ (**) \Rightarrow h=\dfrac{3\cdot3072}{64\sqrt3} = \dfrac{3\cdot48}{\sqrt3} = \dfrac{\sqrt3\cdot\sqrt3\cdot48}{\sqrt3} = 48\sqrt3\  inches


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