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3 years ago

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Santiago, Erin, Javier, and Kayla formed a team for their school's annual egg-and-spoon race. Each person had to carry an egg ba

lanced on a spoon for an equal part of the total length of the race, which was 10 laps around the gym. How far did each person have to carry the egg?

1 answer:

Verizon [17]3 years ago

3 0

Don’t press it it’s a fake link that will hack u

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Doune Punowing:

nataly862011 [7]

The length of pathway is 10 inches on map.

Step-by-step explanation:

Given,

Total distance = 350 miles

According to map,

1 inch = 35 miles

Let, x be the number of inches on map.

Therefore, using proportion;

Inch : mile :: inch : mile

$1:35::x:350\\$

Product of mean = Product of extreme

$35*x=350*1\\35x=350\\$

Dividing both sides by 35;

$\frac{35x}{35}=\frac{350}{35}\\x=10$

The length of pathway is 10 inches on map.

Keywords: Ratio, proportion

Learn more about proportions at:

#LearnwithBrainly

8 0

3 years ago

What would be 1/2÷10 this is dumb i know but its so annoying!!!

Veseljchak [2.6K]

Answer: 1/20 or 0.05

Step-by-step explanation:

6 0

3 years ago

Read 2 more answers

What is the appropriate sequence of events for protein synthesis?

Alborosie

The correct sequence of events in protein synthesis is transcription, then translation.

7 0

3 years ago

Find the variance of this probability distribution. Round to two decimal places.

attashe74 [19]

Answer:

Variance = 4.68

Step-by-step explanation:

The formula for the variance is:

$\sigma^{2} =\frac{\Sigma(X- \mu)^{2}}{N} \\or \\ \sigma^{2} =\frac{\Sigma(X)^{2}}{N} -\mu^{2} \\$

Where:

$X: Values \\\mu: Mean \\N: Number\ of\ values$

The mean can be calculated as each value multiplied by its probability

$\mu = 0*0.4 + 1*0.3 + 2*0.1+3*0.15+ 4*0.05=1.15$

$\frac{\Sigma (X)^{2}}{N} =\frac{(0^{2}+1^{2}+2^{2}+3^{2}+4^{2})}{5} =6$

Replacing the mean and the summatory of X:

$\sigma^{2} = \frac{\Sigma(X)^{2}}{N} -\mu^{2} \\= 6 - 1.15^{2}\\= 4.6775$

4 0

4 years ago

What goes in the space? (3x − ...)2 = 9x2−6x+1<br> I will give points and brainliest!

Crazy boy [7]

${(x - y)}^{2} = {x}^{2} - 2xy + {y}^{2}$

$(3x - ...)^{2} = 9 {x}^{2} - 6x + 1 \\ {(3x - 1)}^{2} = 9 {x}^{2} -6x + 1$

6 0

4 years ago