1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
juin [17]
3 years ago
5

Given that h(x) = x + 8 and g(x) = VX-3, find (g + h)(3), if it exists.

Mathematics
1 answer:
kari74 [83]3 years ago
5 0

Given that h(x) = x + 8 and g(x) = VX-3, find (g + h)(3), if it exists.

Select the correct choice below and fill in any answer boxes within your choice.

You might be interested in
Lorraine writes the equation shown.
Levart [38]

Answer:

a relation and a function

= A

Step-by-step explanation:

6 0
3 years ago
Read 2 more answers
82 x3 +4 +8 +5 +3<br> I KNOW THE ANSWER JUST SOME POINTS FOR FREE
vichka [17]

Answer:

266

Step-by-step explanation:

5 0
3 years ago
Please help I really do not understand its turned in today. I WILL GIVE BRAINLIEST :)
8090 [49]

Answer:

Total area of new carpeting installed: 368

Step-by-step explanation:

What I did is too complicated to write down, so I'll just show you the math:

(12 * 8) * 2 (The area of the bedrooms)

11 * 16 (The area of the livingroom)

6 0
3 years ago
The price p of a pizza is $6.45 plus $0.90 for each of the t toppings on the pizza
Julli [10]
Wats the question?????????

8 0
4 years ago
Anyone can help me solve this equation using cross multiplying
Natali5045456 [20]

9514 1404 393

Answer:

  x = 1 or 5

Step-by-step explanation:

The notion of "cross-multiplying" is the idea that the numerator on the left is multiplied by the denominator on the right, and the numerator on the right is multiplied by the denominator on the left. This looks like ...

  \displaystyle \frac{x-1}{7}=\frac{2x-2}{3x-1}\ \longrightarrow\ (x-1)(3x-1)=(7)(2x-2)

Then the solution proceeds by eliminating parentheses, and solving the resulting quadratic equation.

  3x^2-4x+1=14x-14\\\\3x^2-18x+15=0\qquad\text{subtract $14x-14$}\\\\x^2-6x+5=0 \qquad\text{divide by 3}\\\\(x-1)(x-5)=0\qquad\text{factor}\\\\x\in\{1,5\}

_____

<em>Comment on "cross multiply"</em>

Like a lot of instructions in Algebra courses, the idea of "cross multiply" describes <em>what the result looks like</em>. It doesn't adequately describe how you get there. The <em>one and only rule</em> in solving Algebra problems is "<em>whatever is done to one side of the equation must also be done to the other side of the equation</em>." If you multiply one side by one thing and the other side by a different thing, you are violating this rule.

What looks like "cross multiply" is really "<em>multiply by the product of the denominators</em> and cancel like terms from numerator and denominator." Here's what that looks like with the intermediate steps added.

  \displaystyle \frac{x-1}{7}=\frac{2x-2}{3x-1}\\\\\frac{x-1}{7}\times7(3x-1)=\frac{2x-2}{3x-1}\times7(3x-1)\\\\(x-1)(3x-1)=(2x-2)(7)\qquad\textit{looks like}\text{ cross multiply}

8 0
3 years ago
Other questions:
  • 6.45 t0 the nearest whole number
    14·2 answers
  • What is negative 3/8 plus 7/8
    14·2 answers
  • Help with number two
    8·1 answer
  • 132 minutes to 5 hours
    9·1 answer
  • PLEASE HELP ME!!!!!!!!!!!!!!!!!!
    5·1 answer
  • The volume of a box(V) varies directly with its length(l). Using k for the constant of proportionality, express the relationship
    11·1 answer
  • What is the greatest whole number that can be multiplied by 7 to result in a product that is less than 100,000?
    8·1 answer
  • NEED HELP ASAP GIVING 60 POINTS AND BRAINLIEST !!!What is the algebraic expression for the following word phrase: the quotient o
    13·1 answer
  • VERY EASY, WILL GIVE 50 POINTS FOR CORRECT ANSWER ASAP AND WILL GIVE BRAINLIEST.
    12·1 answer
  • Philip tiene 8 bolas rojas, 3 bolas verdes, 6 bolas amarillas, 13 bolas negras y 15 bolas azules en su bolsa. ¿cuál es la media,
    12·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!