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hichkok12 [17]
3 years ago
12

P(5,-3) Q(2,4) find distance​

Mathematics
1 answer:
Alenkinab [10]3 years ago
7 0

Answer: \sqrt{58}

The distance between the coordinates of the two points is measured by the Distance formula

Step-by-step explanation:

The distance between two points P(x1,y1) and Q(x2,y2) is measured by Distance formula i.e Distance= \sqrt{}(x2-x1)²+(y2-y1)²

So, the distance between the two points P(5,-3) and Q(2,4) can be measured by

Distance PQ = \sqrt{}(2-5)²+(4-(-3))²

               PQ = \sqrt{}  (-3)²+7²

               PQ= \sqrt{} 9+49

               PQ=\sqrt{}58

So,the distance of PQ is \sqrt{58}

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The distance between the two buildings is 844.23 feet apart, we go this answer by simply applying the SOH CAH TOA method

<h3>Trigonometry</h3>

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Tan 35 = 400/x

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Add that to both sides of the equation.

Now you have:

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Solve for x, , take the square root of both sides:

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