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3 years ago

S=hp+2b solve for h i forgot the word to decribe how i forgot to do tis

Mathematics

1 answer:

irga5000 [103]3 years ago

5 0

To solve for h, you need to isolate/get h by itself in the equation:

s = hp + 2b Subtract 2b on both sides

s - 2b = hp + 2b - 2b

s - 2b = hp Divide p on both sides to get h by itself

$\frac{s-2b}{p} =\frac{hp}{p}$

$\frac{s-2b}{p} =h$

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$c_{0} \cdot f_{in} - c(t) \cdot f_{out} = V_{tank}(t) \cdot \frac{dc(t)}{dt} + \frac{dV_{tank}(t)}{dt} \cdot c(t)$

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Since there is no accumulation within the tank, expression is simplified to this:

$c_{0} \cdot f_{in} - c(t) \cdot f_{out} = V_{tank}(t) \cdot \frac{dc(t)}{dt}$

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The instantaneous amount of salt in the tank is:

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