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Sonbull [250]
3 years ago
12

The area of a trapezoid is 18 square meters. One base is 3 meters long and the other is 6 meters long. Find the height of the tr

apezoid. Step 2 of 3 : Without substitution, solve the formula chosen in the previous step for the unknown variable in terms of the known variable(s).
Mathematics
1 answer:
aleksley [76]3 years ago
8 0

Answer:

height = 4 meters

h = 2A / ( a +  b )

Step-by-step explanation:

Let A represent the area of the trapezoid, h, the height a, the length of one base and b, the length of the other base

Area of a trapezoid, A = ( a + b)* h / 2

Now let's slot in the given values

A= 18 sq meters

a = 3 meters

b = 6 meters

we have;

18 = ( 3 + 6 ) * h /2

18 = 9 * h /2

Cross multiply

18*2 = 9h

36 = 9h

divide both sides by the coefficient of h (9)

4 = h

therefore, h = 4 meters

To solve for h without substituting

From A = ( a + b )* h /2

cross multiply

2*A = ( a + b )* h

divide both sides by ( a + b )

2A / ( a + b ) = h

therefore,

h = 2A / ( a +  b )

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3 0
3 years ago
What is an example of when you would want consistent data and, therefore, a small standard deviation?
steposvetlana [31]

Answer:

12.1, 12.3,12.4,12.5,12.3,12.1,12.2

\bar X= \frac{12.1+12.3+12.4+12.5+12.3+12.1+12.2}{7}=12.271

And for the standard deviation we can use the following formula:

s= \sqrt{\frac{\sum_{i=1}^n (X_i -\bar X)^2}{n-1}}

And after replace we got:

s = 0.1496

And as we can ee we got a small value for the deviation <1 on this case.

Step-by-step explanation:

For example if we have the following data:

12.1, 12.3,12.4,12.5,12.3,12.1,12.2

We see that the data are similar for all the observations so we would expect a small standard deviation

If we calculate the sample mean we can use the following formula:

\bar X=\frac{\sum_{i=1}^n X_i}{n}

And replacing we got:

\bar X= \frac{12.1+12.3+12.4+12.5+12.3+12.1+12.2}{7}=12.271

And for the standard deviation we can use the following formula:

s= \sqrt{\frac{\sum_{i=1}^n (X_i -\bar X)^2}{n-1}}

And after replace we got:

s = 0.1496

And as we can ee we got a small value for the deviation <1 on this case.

8 0
3 years ago
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