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notka56 [123]
3 years ago
11

read the excerpt below and answer the question. as i said these things i got scared. it felt like worms and toads and slimy thin

gs crawling out of my chest, but it also felt good, that this awful side of me had surfaced, at last. what element of plot does the excerpt most likely represent? rising action conclusion falling action climax
Mathematics
2 answers:
Mamont248 [21]3 years ago
7 0

Answer:

The answer is climax hope this helps

Step-by-step explanation:


Yakvenalex [24]3 years ago
5 0
This excerpt is likely to be part of the rising action. It is building up the character via a series of events and is foreshadowing an oncoming climax. This is evident in the statement "that this awful side of me had surfaced, at last". We now know that the character has undergone a major change and the climax is soon to come.
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What is that I have never seen a problem like that. Is this a actual question or are you playing around...‼️
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Last month Jim drove his car 2,718.3 miles. That brought the car’s total mileage to 87,416. What was the car’s mileage before la
stich3 [128]

To solve this problem you must apply the proccedure shown below:

1. You have that Jim drove the car 2,718.3 miles for a total mileage of 87,416.

2. Then, to calculate the mileage before last month, you only need to substract the total mileage given in the exercise above and the mileage drove last month, as following:

87,416miles-2,718.3miles=84,697.7miles

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(\stackrel{x_1}{4}~,~\stackrel{y_1}{1})\qquad (\stackrel{x_2}{2}~,~\stackrel{y_2}{-2}) ~\hfill \stackrel{slope}{m}\implies \cfrac{\stackrel{rise} {\stackrel{y_2}{-2}-\stackrel{y1}{1}}}{\underset{run} {\underset{x_2}{2}-\underset{x_1}{4}}}\implies \cfrac{-3}{-2}\implies \cfrac{3}{2} \\\\\\ \begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-\stackrel{y_1}{1}=\stackrel{m}{\cfrac{3}{2}}(x-\stackrel{x_1}{4})

\stackrel{\textit{multiplying both sides by }\stackrel{LCD}{2}}{2(y-1)=2\left( \cfrac{3}{2}(x-4) \right)}\implies 2y-2 = 3(x-4)\implies 2y-2=3x-12 \\\\\\ -3x+2y-2=-12\implies -3x+2y=-10\implies \stackrel{\times -1\textit{ to both sides}}{3x-2y=10}

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