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Firlakuza [10]
3 years ago
9

The area of a rectangular pool was 120square meters. If the long side in 7 meters plus a number and the width is 6 meters. What

is the value of the variable?
Mathematics
1 answer:
NeX [460]3 years ago
8 0

Answer:

The value of the variable=13 meters

Step-by-step explanation:

Step 1

Express the dimensions of the pool

Length=7+x

width=6

Step 2

Express the area of a rectangle as shown;

A=L×W

where;

A=area of a rectangle

L=length of the rectangle

W=width of the rectangle

In our case;

A=120 m²

L=x+7

W=6

replacing in the equation;

120 m²=(x+7)×6

120=6 x+42

6 x+42=120

6 x=120-42

6 x=78

x=78/6

x=13

The value of the variable=x=13 meters

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For this case we first calculate the rate in blocks per minutes.
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In ΔEFG, the measure of ∠G=90°, the measure of ∠E=6°, and GE = 71 feet. Find the length of EF to the nearest tenth of a foot.
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Step-by-step explanation:

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Crash Hospital Costs. A study was conducts to estimate hospital costs for accident victims who wore seat belts. Twenty randomly
kvv77 [185]

Answer:

a) The 99% confidence interval would be given by (5004.168;12603.832)

b) For this case we can use the lower bound for the confidence interval as estimation, on this case 5004.168. But we need to take in count that this value it's with 99% of confidence and 1% of significance and 1% of probability to commit type Error I

Step-by-step explanation:

1) Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

\bar X =9004 represent the sample mean for the sample  

\mu population mean (variable of interest)

s=5629 represent the sample standard deviation

n=20 represent the sample size  

2) Part a

The confidence interval for the mean is given by the following formula:

\bar X \pm t_{\alpha/2}\frac{s}{\sqrt{n}}   (1)

In order to calculate the critical value t_{\alpha/2} we need to find first the degrees of freedom, given by:

df=n-1=20-1=19

Since the Confidence is 0.99 or 99%, the value of \alpha=0.01 and \alpha/2 =0.005, and we can use excel, a calculator or a table to find the critical value. The excel command would be: "=-T.INV(0.005,19)".And we see that t_{\alpha/2}=2.86

Now we have everything in order to replace into formula (1):

9004-2.86\frac{5629}{\sqrt{20}}=5004.168    

9004+2.86\frac{5629}{\sqrt{20}}=12603.832

So on this case the 99% confidence interval would be given by (5004.168;12603.832)    

3) Part b

For this case we can use the lower bound for the confidence interval as estimation, on this case 5004.168. But we need to take in count that this value it's with 99% of confidence and 1% of significance and 1% of probability to commit type Error I

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If you sell 15 sandwiches in 45 minutes how many will you sell in 3 hours.
lina2011 [118]
You would be able to sell 60 sandwiches in 3 hours

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