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lozanna [386]
3 years ago
6

Please help due tonight !

Mathematics
2 answers:
Travka [436]3 years ago
8 0

Answer: (14 , 15/2)

Step-by-step explanation:

...

Blizzard [7]3 years ago
5 0

Answer:

No, K isn't the midpoint of JL

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A bacteria culture initially contains 2000 bacteria and doubles every half hour.
dsp73

<em>Answer:</em>

<em>Can be found below</em>

<em>Step-by-step explanation:</em>

<em>Part A:</em>

<em>So we know that the bacteria doubles every (30) minutes.</em>

<em>2000 times 2 equals 4000 (30 minutes)</em>

<em>4000 times 2 equals 8000 (1 hour)</em>

<em>Answer for Part A:</em>

<em>8000 bacteria</em>

<em>Part B:</em>

<em>Now we do this function 2000(2)^14 (30 minutes long)</em>

<em>Answer to Part B: </em>

<em>I believe the answer is 32,768,000 (Please correct me if I'm wrong) </em>

<em>Hope I could help!! Have a great day/night!</em>

<em>Any constructional messages are greatly appreciated!!</em>

5 0
3 years ago
What is 10984 rounded to the nearest 10 thousand?
Gelneren [198K]
10984 rounded to the nearest thousand is 11,000  

3 0
3 years ago
HELP ON BOTH HAVE 2 MINUTE'S LEFT. NO LINKS. I JUST NEED SIMPLE ANSWERS
Lady_Fox [76]

Answer:

Q1: 48

Q2: 59

Step-by-step explanation:

8 0
3 years ago
Read 2 more answers
Find the volume of the cone
Anuta_ua [19.1K]

Volume= 37. 7

V=π r² h/3 = π · 22 · 9/3 ≈37.69911

I hope this helps!

8 0
2 years ago
Find the sum of the first one hundred positive integers. see fig 6.26
nignag [31]
Here's a pattern to consider:
1+100=101
2+99=101
3+98=101
4+97=101
5+96=101
.....
This question relates to the discovery of Gauss, a mathematician. He found out that if you split 100 from 1-50 and 51-100, you could add them from each end to get a sum of 101. As there are 50 sets of addition, then the total is 50×101=5050
So, the sum of the first 100 positive integers is 5050.

Quick note
We can use a formula to find out the sum of an arithmetic series:
s =  \frac{n(n + 1)}{2}
Where s is the sum of the series and n is the number of terms in the series. It works for the above problem.
8 0
3 years ago
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