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Maksim231197 [3]
3 years ago
14

Valerie is 64 inches tall about how many centimeters tall is Valerie

Mathematics
2 answers:
Grace [21]3 years ago
7 0
There are about 163 centimeters in 64 inches.

There are 2.54 centimeters in 1 inch. Multiply 2.54 times 64 and you'll get 162.56  centimeters, which is about 163 centimeters.
Elanso [62]3 years ago
4 0
162.56cm or if you round it, 163cm
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Can someone answer this too?!?!
Ksenya-84 [330]
1/6 plus 2/3 = 5/6 so you do 24 - 5/6 which is 23 1/6
8 0
4 years ago
The admission fee at an amusement park is $12, and each ride costs $3.50. The park also offers an all-day pass with unlimited ri
gavmur [86]
Solve using system of equations.
y=total money spent, x=amount of rides
y=12+3.5x
y=33
Solve! Set them equal to each other
12+3.5x=33
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6 0
3 years ago
Simplify the expression given below. 1/(2x^2-4x) -2/x
Sholpan [36]

Answer:

(9 - 4 x)/(x (2 x - 4))

Step-by-step explanation:

Simplify the following:

1/(2 x^2 - 4 x) - 2/x

Put each term in 1/(2 x^2 - 4 x) - 2/x over the common denominator x (2 x - 4): 1/(2 x^2 - 4 x) - 2/x = ((x (2 x - 4))/(2 x^2 - 4 x))/(x (2 x - 4)) - (2 (2 x - 4))/(x (2 x - 4)):

((x (2 x - 4))/(2 x^2 - 4 x))/(x (2 x - 4)) - (2 (2 x - 4))/(x (2 x - 4))

A common factor of 2 x - 4 and 2 x^2 - 4 x is 2 x - 4, so (x (2 x - 4))/(2 x^2 - 4 x) = (x (2 x - 4))/(x (2 x - 4)):

((x (2 x - 4))/(x (2 x - 4)))/(x (2 x - 4)) - (2 (2 x - 4))/(x (2 x - 4))

(x (2 x - 4))/(x (2 x - 4)) = 1:

1/(x (2 x - 4)) - (2 (2 x - 4))/(x (2 x - 4))

1/(x (2 x - 4)) - (2 (2 x - 4))/(x (2 x - 4)) = (1 - 2 (2 x - 4))/(x (2 x - 4)):

(1 - 2 (2 x - 4))/(x (2 x - 4))

-2 (2 x - 4) = 8 - 4 x:

(8 - 4 x + 1)/(x (2 x - 4))

Add like terms. 1 + 8 = 9:

Answer: (9 - 4 x)/(x (2 x - 4))

3 0
4 years ago
Read 2 more answers
Marcus went on a diet and now weighs 140 lb he originally weighed 175 lb what percent of his weight did he lose
yawa3891 [41]

Marcus lost 35 pounds. 35/175 is 20%.


8 0
3 years ago
What is the square root of 2131?
snow_lady [41]

Answer:

14.5945195193

Step-by-step explanation:

8 0
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