Answer:A)35choices
B)475,020choices
C)132choices
D)0.000278
E)0.000166
Step-by-step explanation:
Given 7poultry items represented by 7p
10 red meat items=10R
12 vegetarian items=12V
@
A)there are 7combination 3ways of selecting 3out of 7 poultry items
From the formula nCr=n!/(n-r)!r!
7C3=7!/(7-3)!3!=7!/4!×3!=35choices
b)total items available=7p+10R+12V(denotation explained above)=29items
Choosing 6items implies
29C6=29!/(29-6)!×6!
29!/23!×6!=475,020 ways
C)7C2+10C2+12C2
7!/5!2!+10!/8!2!+12!/10!2!
21+45+66=132 choices
D) probability (choosing 2items from each class)=
7C2+10C2+12C2/29C6
Where 29C6 represent total probable.
21+45+66/29!/23!6!
=132/475020=0.000278choices
E)for meats to be in the majority on a 6choices selection impliee that vegetarian items will be
0,1 or2i.e combination of vegetarian and meat will be(0,6)or(1,5)or(2,4) .
Prob(0veg)+prob(1veg item) or prob(2veg items)
12C0+12C1+12C2/29C6
=1+12+66/475,020
=0.000166
The three scores are 86, 74, and an unknown score x. The average (i.e. the sum divided by how many there are) is 80, so we have
Multiply both sides by 3 and you get
Subtract 160 from both sides to get
Note: you could solve this exercise very quickly if you notice that the two numbers, 86 and 74, are symmetrical with respect to 80, which is the average. So, the third number must be the average.
Each friend got $1.30 I hope this helps!!!!
