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Orlov [11]
3 years ago
8

George is collecting baseball cards he has 29 stacks of cars with 4 in each stack how many cars does he have altogether

Mathematics
2 answers:
Effectus [21]3 years ago
8 0

29 \times 4 = 116
116 cars
mario62 [17]3 years ago
7 0

He has 116 cards altogether.

29 stacks of cards with 4 in each stack

29(4)

116

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The label on a 1 1/2pound bag of wildflowers seeds states that it will cover an area of 375 square feet. Based on this informati
BaLLatris [955]

Answer:

250 square feet

Step-by-step explanation:

This problem can be easily solved using ratios.

It says that  1\frac{1}{2} pound covers 375 sq. ft.

So, how much would 1 pound cover?

Let 1 pound cover "x" pounds. We can setup up two ratios and equate them. Then cross multiply and solve for x.

Note:  Pounds on numerator and Square Feet on denominator

\frac{1\frac{1}{2}}{375}=\frac{1}{x}\\1\frac{1}{2}*x=375*1\\1\frac{1}{2}x=375\\\frac{3}{2}x=375\\x=\frac{375}{\frac{3}{2}}\\x=375*\frac{2}{3}\\x=250

Hence, 1 pound of wildflower seeds will cover an area of 250 square feet

4 0
4 years ago
the first four terms in an arithmetic sequence are $x y$, $x - y$, $xy$, and $x/y$, in that order. what is the fifth term?
olga2289 [7]

When the first four terms in an arithmetic sequence are x+y, x-y, xy and x÷y, then the fifth term will be \frac{123}{40}

A sequence of numbers in which every term (except the first term) is obtained by adding a constant number to the previous term is called an arithmetic sequence

In given arithmetic sequence

The first term = x+y

The second term = x-y

Then, the common difference= (x-y)-(x+y)

x-y-x-y= -2y

The third term = x-y+(-2y)

x-y-2y= x-3y

In question third term is given as xy

So both are equal

x-3y=xy

-3y=xy-x

-3y=x(y-1)

x= \frac{-3y}{y-1}

Similarly fourth term will be

x-3y-2y=x-5y

x-5y=\frac{x}{y}

substitute the value of x  in the equation

\frac{-3y}{y-1}-5y=\frac{\frac{-3y}{y-1} }{y} \\\frac{-3y}{y-1} -5y=\frac{-3}{y-1}\\ -3y-5y(y-1)=-3\\-3y-5y^{2}+5y=-3\\ -5y^{2} +2y+3=0\\5y^{2} -2y-3=0

Split the middle term and factorize it

5y^{2}+3y-5y-3=0\\y(5y+3)-1(5y+3)=0\\

(y-1)(5y+3)=0

y=1,\frac{-3}{5}

y cannot be equal to 1, because the third term and fourth term will become x.

y=\frac{-3}{5}

substitute the value of y in the equation of x
x=\frac{-3y}{y-1} \\=\frac{-3\frac{-3}{5} }{\frac{-3}{5}-1 }\\ =\frac{-9}{8}

The fifth term= \frac{x}{y}+(-2y)=\frac{x}{y} -2y

\frac{\frac{-9}{8} }{\frac{-3}{5} }-2\frac{-3}{5}  =\frac{123}{40}

Hence, when the first four terms in an arithmetic sequence are x+y, x-y, xy and x÷y, then the fifth term will be \frac{123}{40}

Learn more about Arithmetic sequence here

brainly.com/question/15412619

#SPJ4

5 0
2 years ago
A model train is built to a 1 in. : 64 in. scale. Find the actual length for a peice on the model that is 0.75 in.​
slavikrds [6]

Answer:it should be 48 in

im not 100% sure

Step-by-step explanation:

7 0
3 years ago
Find the volume of the region between the cylinder z=3y^2 and the xy-plane that is bounded by the planes x=0,x=1 ,y=-1 and . z =
son4ous [18]

Answer:

The volume of the region V = 2

Step-by-step explanation:

Given that:

z_1 = 3y^2 ;

where initially;

z_o = 0; \ x_o = 0;  \ x_1 = 1; \  y_o= -1;  \ y_1 = 1

The volume of the region is given by a triple which is expressed as:

V = \int_x \int_y \int_z \ dz \ dy \ dx

V = \int \limits ^{x_1 = 1}_{x_o=0}  \int \limits  ^{y_1 = 1}_{y_o=-1}    \int \limits ^{z_1 = 3y^2}_{z_o=0}  \ dz \ dy \ dx

V = \int \limits ^{1}_{0}  \int \limits  ^{ 1}_{-1}    \int \limits ^{3y^2}_{0}  \ dz \ dy \ dx

V = \int \limits ^{1}_{0}  \int \limits  ^{ 1}_{-1}   \Bigg [z \Bigg]^{3y^2}_{0} \ dy \ dx

V = \int \limits ^{1}_{0}  \int \limits  ^{ 1}_{-1}   \Bigg [3y^2 \Bigg]  \ dy \ dx

V = \int \limits ^{1}_{0}   \Bigg [\dfrac{3y^3}{3} \Bigg]^1_{-1}   \ dx

V = \int \limits ^{1}_{0}   \Bigg [\dfrac{3(1)^3}{3}- \dfrac{3(-1)^3}{3} \Bigg]   \ dx

V = \int \limits ^{1}_{0}   \Bigg [1-(-1)\Bigg]   \ dx

V =2  \Bigg [x \Bigg] ^1_0

V = 2

Thus, the volume of the region is 2

3 0
3 years ago
-5v^2+17v-6? Factor completely
elixir [45]
If V's are the variables, both V's would = 2/5 and 3.
4 0
3 years ago
Read 2 more answers
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