The answer is [-1,26]. The range between 4 and 9 is 5, and the range between 8 and -10 is 18, so you'd apply this to [4, 8] in order to find the other endpoint.
First, find any zero of the polynomial. Since you didn't ask for work, I'll assume it's okay if I use my calculator. Your given polynomial has only one real root which is x=-4.
Now we use the rule that x-a divides the polynomial where a is a zero of said polynomial.
So x+4 divides 2x^3+2x^2-19x+20.
<span>(2x^3+2x^2-19x+20) / (x+4 equals 2x^2-6x+5).
If we factor out a two, we can use the quadratic formula.
2(x^2-3x+2.5) so we have x = (-(-3)+/-(9-4*1*2.5)^(1/2))/2*1)=(3+i)... or (3-i)/2 Where i is the square root of negative one. final answer:
2x^3+2x^2-19x+20=0
then x=-4, (3+i)/2, or (3-i)/2
</span>we have two imaginary number.
I hope it helped you
So, here is exactly how you would do this:
-3m-2e if m=6 and e=1
We know the values of e and m. We can plug these in to evaluate.
Simply replace the number 6 in place of m and 1 in place of e in -3m-2e
-3m-2e Original expression
-3(6)-2(1) With values plugged in
-18-2 Simplified
-20 Final answer
Our final answer would therefore be: -20
Answer:
2, 3, 7
Step-by-step explanation:
Since you know your multiplication tables, you know that ...
42 = 6 × 7
and
6 = 2 × 3
The numbers 2, 3, and 7 are prime numbers (not further divisible). This list is in order least to greatest, so is the combination of the lock.
Answer:
2, 3, and 4 of Ed
Step-by-step explanation:
Saw another answer of brainly .