The probability that all of the next ten customers who want this racket can get the version they want from current stock is 0.821
<h3>How to solve?</h3>
Given: currently has seven rackets of each version.
Then the probability that the next ten customers get the racket they want is P(3≤X≤7)
<h3>Why P(3≤X≤7)?</h3>
Note that If less than 3 customers want the oversize, then more than 7 want the midsize and someone's going to miss out.
X ~ Binomial (n = 10, p = 0.6)
P(3≤X≤7) = P(X≤7) - P(X≤2)
From Binomial Table:
= 0.8333 - 0.012
= 0.821
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Answer:
Should be D.
I don't know why it won't let me respond with under 20 characters.
U=2x+3, x=u/2-3/2
u^2+8u+11=0
u1=(-8+sqrt(64-44))/2=-4+sqrt(5)
u2=-4-sqrt(5)
x1=u1/2-3/2=-7/2+sqrt(5)/2
x2=u2-3/2=-7/2-sqrt(5)/2
(f + g)(x) = f(x) + g(x) therefore (f + g)(4) = f(4) + g(4)
